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Two charges of equal magnitude and at a distance r exert a force F on each other.If the charges are halved and distance between them is doubled,then the new force acting on each charge is?
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Two charges of equal magnitude and at a distance r exert a force F on ...
Explanation:

Original scenario:
- Two charges of equal magnitude and at a distance r exert a force F on each other.

Scenario after modification:
- Charges are halved and distance between them is doubled.

Calculation of new force:
- Let the original charges be q and the original distance be r.
- The original force between the charges is given by Coulomb's law: F = k(q^2/r^2), where k is the Coulomb's constant.
- After halving the charges and doubling the distance, the new force can be calculated using the same formula with the new values of charge and distance.

New force formula:
- Let q' be the new charge (q/2) and r' be the new distance (2r).
- The new force can be calculated as: F' = k((q/2)^2/(2r)^2) = k(q^2/16r^2) = (1/16)F

Conclusion:
- The new force acting on each charge is 1/16 times the original force.
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Two charges of equal magnitude and at a distance r exert a force F on each other.If the charges are halved and distance between them is doubled,then the new force acting on each charge is?
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