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If one of the zeroes of kx²+3x+k is 2, then k=?
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If one of the zeroes of kx²+3x+k is 2, then k=?
Explanation:
To find the value of k when one of the zeroes of the quadratic equation kx² + 3x + k is given as 2, we can use the fact that the sum of the zeroes of a quadratic equation is equal to -b/a and the product of the zeroes is equal to c/a.

Given:
One zero of the equation kx² + 3x + k is 2.

Sum of zeroes:
The sum of the zeroes of the quadratic equation kx² + 3x + k is -b/a.
In this case, the sum of the zeroes is 2 and k = 2.
Therefore, we have:
2 = -3/k
2k = -3
k = -3/2

Product of zeroes:
The product of the zeroes of the quadratic equation kx² + 3x + k is c/a.
In this case, the product of the zeroes is k.
Therefore, we have:
k = 2 * -3/2
k = -3
Therefore, the value of k is -3.
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If one of the zeroes of kx²+3x+k is 2, then k=?
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