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If tan2A+B=root3 and cot3A-B =root 3 find a and B?
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If tan2A+B=root3 and cot3A-B =root 3 find a and B?
Given Information:
tan(2A+B) = √3
cot(3A-B) = √3

Finding the Values of A and B:

Using Trigonometric Identities:
We know that tan(2A+B) = (√3) can be expressed as tan(60 degrees) = (√3)
Similarly, cot(3A-B) = (√3) can be expressed as cot(60 degrees) = (√3)

Calculating the Values of A and B:
From the trigonometric identities, we can deduce that:
2A + B = 60 degrees
3A - B = 60 degrees
Solving the above two equations simultaneously, we get:
A = 20 degrees
B = 20 degrees
Therefore, the values of A and B are 20 degrees each.

Explanation:
- The given trigonometric identities help us to find the values of A and B by equating them to standard trigonometric ratios.
- By solving the equations obtained from the identities, we can determine the values of A and B as 20 degrees each.
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If tan2A+B=root3 and cot3A-B =root 3 find a and B?
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