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A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.?.

Solutions for A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.? in English & in Hindi are available as part of our courses for UPSC. Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.

Here you can find the meaning of A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.? defined & explained in the simplest way possible. Besides giving the explanation of A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.?, a detailed solution for A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.? has been provided alongside types of A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.? theory, EduRev gives you an ample number of questions to practice A npn bipolar transistor having uniform doping of NE=1018 cm-3 , NB=1016 cm-3 and NC=6×1015 cm-3 is operating in the inverse-active mode with VBE= -2 V and VBC = 0.6 V. (a) Calculate the minority carrier concentration at x= xB and x //=0. 3 (b) Calculate the Base-Collector junction voltage (VBC), at which the minority carrier electron concentration at x //= xB is 20% of the majority carrier hole concentration.? tests, examples and also practice UPSC tests.