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What force will be required to punch a hole of 16 mm diameter in a plate of 25 mm
thickness? The shear strength of the plate is 340 MPa. What compressive stress would
be induced in the punch?
thickness? The shear strength of the plate is 340 MPa. What compressive stress would
be induced in the punch?
Most Upvoted Answer
What force will be required to punch a hole of 16 mm diameter in a pla...
Calculating the force required:
- The area of the hole can be calculated using the formula for the area of a circle: A = πr^2, where r is the radius of the hole (which is half of the diameter).
- Given that the diameter is 16 mm, the radius (r) is 8 mm (or 0.008 m).
- Therefore, the area of the hole is A = π(0.008)^2 = 0.000201 m^2.
- The force required to punch the hole can be calculated using the formula: Force = Shear strength x Area.
- Substituting the values, we get Force = 340 MPa x 0.000201 m^2 = 68.34 kN.
Calculating the compressive stress:
- The compressive stress induced in the punch can be calculated using the formula: Stress = Force / Area of the punch.
- The area of the punch can be calculated in a similar way as the hole, using the formula A = πr^2.
- Assuming the punch has the same diameter as the hole, the radius (r) is 8 mm (or 0.008 m).
- Therefore, the area of the punch is A = π(0.008)^2 = 0.000201 m^2.
- Substituting the values, we get Stress = 68.34 kN / 0.000201 m^2 = 340 MPa.
Therefore, the compressive stress induced in the punch would be 340 MPa, which is equal to the shear strength of the plate. This means that the punch is applying a force that is equal to the maximum shear strength of the plate, which is required to punch a hole of 16 mm diameter in a plate of 25 mm thickness.
- The area of the hole can be calculated using the formula for the area of a circle: A = πr^2, where r is the radius of the hole (which is half of the diameter).
- Given that the diameter is 16 mm, the radius (r) is 8 mm (or 0.008 m).
- Therefore, the area of the hole is A = π(0.008)^2 = 0.000201 m^2.
- The force required to punch the hole can be calculated using the formula: Force = Shear strength x Area.
- Substituting the values, we get Force = 340 MPa x 0.000201 m^2 = 68.34 kN.
Calculating the compressive stress:
- The compressive stress induced in the punch can be calculated using the formula: Stress = Force / Area of the punch.
- The area of the punch can be calculated in a similar way as the hole, using the formula A = πr^2.
- Assuming the punch has the same diameter as the hole, the radius (r) is 8 mm (or 0.008 m).
- Therefore, the area of the punch is A = π(0.008)^2 = 0.000201 m^2.
- Substituting the values, we get Stress = 68.34 kN / 0.000201 m^2 = 340 MPa.
Therefore, the compressive stress induced in the punch would be 340 MPa, which is equal to the shear strength of the plate. This means that the punch is applying a force that is equal to the maximum shear strength of the plate, which is required to punch a hole of 16 mm diameter in a plate of 25 mm thickness.
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What force will be required to punch a hole of 16 mm diameter in a plate of 25 mm thickness? The shear strength of the plate is 340 MPa. What compressive stress would be induced in the punch?
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What force will be required to punch a hole of 16 mm diameter in a plate of 25 mm thickness? The shear strength of the plate is 340 MPa. What compressive stress would be induced in the punch? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about What force will be required to punch a hole of 16 mm diameter in a plate of 25 mm thickness? The shear strength of the plate is 340 MPa. What compressive stress would be induced in the punch? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What force will be required to punch a hole of 16 mm diameter in a plate of 25 mm thickness? The shear strength of the plate is 340 MPa. What compressive stress would be induced in the punch?.
What force will be required to punch a hole of 16 mm diameter in a plate of 25 mm thickness? The shear strength of the plate is 340 MPa. What compressive stress would be induced in the punch? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about What force will be required to punch a hole of 16 mm diameter in a plate of 25 mm thickness? The shear strength of the plate is 340 MPa. What compressive stress would be induced in the punch? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What force will be required to punch a hole of 16 mm diameter in a plate of 25 mm thickness? The shear strength of the plate is 340 MPa. What compressive stress would be induced in the punch?.
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