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A 220MM×16MM double cover butt joint is applied with six (6) reverts of diameter 24MM each. The thickness of the cover plates are 10MM each. if the allowable stress are tension=114N/MM², shear stress=95N/MM² and crushing stress=180N/MM²
Determine per width of joint
(I) safe load carried by the joint
(ii) efficiency of the joint?
Determine per width of joint
(I) safe load carried by the joint
(ii) efficiency of the joint?
Most Upvoted Answer
A 220MM×16MM double cover butt joint is applied with six (6) reverts o...
Safe Load Carried by the Joint:
- First, calculate the effective area of the joint:
Effective area = (Width of joint - Diameter of reverts) × Thickness of cover plate
= (220 - 24*6) × 10
= 220 × 10 = 2200 mm²
- Calculate the safe load for tension:
Safe load for tension = Allowable stress for tension × Effective area
= 114 N/mm² × 2200 mm²
= 250800 N
- Calculate the safe load for shear:
Safe load for shear = Allowable stress for shear × Effective area
= 95 N/mm² × 2200 mm²
= 209000 N
- Calculate the safe load for crushing:
Safe load for crushing = Allowable stress for crushing × Area of reverts
= 180 N/mm² × (π*(24/2)^2) × 6
= 180 N/mm² × 452.39 mm² × 6
= 487846.8 N
- The safe load carried by the joint is the minimum of the above values, which is 209000 N (safe load for shear).
Efficiency of the Joint:
- Efficiency of the joint = (Safe load carried by the joint / Total load applied) × 100%
= (209000 N / Total load applied) × 100%
- Since the total load applied is not given in the question, the efficiency of the joint cannot be calculated accurately without this information.
- First, calculate the effective area of the joint:
Effective area = (Width of joint - Diameter of reverts) × Thickness of cover plate
= (220 - 24*6) × 10
= 220 × 10 = 2200 mm²
- Calculate the safe load for tension:
Safe load for tension = Allowable stress for tension × Effective area
= 114 N/mm² × 2200 mm²
= 250800 N
- Calculate the safe load for shear:
Safe load for shear = Allowable stress for shear × Effective area
= 95 N/mm² × 2200 mm²
= 209000 N
- Calculate the safe load for crushing:
Safe load for crushing = Allowable stress for crushing × Area of reverts
= 180 N/mm² × (π*(24/2)^2) × 6
= 180 N/mm² × 452.39 mm² × 6
= 487846.8 N
- The safe load carried by the joint is the minimum of the above values, which is 209000 N (safe load for shear).
Efficiency of the Joint:
- Efficiency of the joint = (Safe load carried by the joint / Total load applied) × 100%
= (209000 N / Total load applied) × 100%
- Since the total load applied is not given in the question, the efficiency of the joint cannot be calculated accurately without this information.
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A 220MM×16MM double cover butt joint is applied with six (6) reverts of diameter 24MM each. The thickness of the cover plates are 10MM each. if the allowable stress are tension=114N/MM², shear stress=95N/MM² and crushing stress=180N/MM²Determine per width of joint (I) safe load carried by the joint (ii) efficiency of the joint?
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A 220MM×16MM double cover butt joint is applied with six (6) reverts of diameter 24MM each. The thickness of the cover plates are 10MM each. if the allowable stress are tension=114N/MM², shear stress=95N/MM² and crushing stress=180N/MM²Determine per width of joint (I) safe load carried by the joint (ii) efficiency of the joint? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A 220MM×16MM double cover butt joint is applied with six (6) reverts of diameter 24MM each. The thickness of the cover plates are 10MM each. if the allowable stress are tension=114N/MM², shear stress=95N/MM² and crushing stress=180N/MM²Determine per width of joint (I) safe load carried by the joint (ii) efficiency of the joint? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 220MM×16MM double cover butt joint is applied with six (6) reverts of diameter 24MM each. The thickness of the cover plates are 10MM each. if the allowable stress are tension=114N/MM², shear stress=95N/MM² and crushing stress=180N/MM²Determine per width of joint (I) safe load carried by the joint (ii) efficiency of the joint?.
A 220MM×16MM double cover butt joint is applied with six (6) reverts of diameter 24MM each. The thickness of the cover plates are 10MM each. if the allowable stress are tension=114N/MM², shear stress=95N/MM² and crushing stress=180N/MM²Determine per width of joint (I) safe load carried by the joint (ii) efficiency of the joint? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A 220MM×16MM double cover butt joint is applied with six (6) reverts of diameter 24MM each. The thickness of the cover plates are 10MM each. if the allowable stress are tension=114N/MM², shear stress=95N/MM² and crushing stress=180N/MM²Determine per width of joint (I) safe load carried by the joint (ii) efficiency of the joint? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 220MM×16MM double cover butt joint is applied with six (6) reverts of diameter 24MM each. The thickness of the cover plates are 10MM each. if the allowable stress are tension=114N/MM², shear stress=95N/MM² and crushing stress=180N/MM²Determine per width of joint (I) safe load carried by the joint (ii) efficiency of the joint?.
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