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A father is seven times as old as his son five years from now he will be your times as old as his son .Find the present age of both?
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A father is seven times as old as his son five years from now he will ...
Given information:
Let the present age of the son be x years.
The father is seven times as old as his son, so the present age of the father is 7x years.

Five years from now:
The son's age will be x + 5 years.
The father's age will be 7x + 5 years.

Equation based on the given information:
According to the problem, five years from now, the father will be four times as old as his son.
So, we can write the equation:
7x + 5 = 4(x + 5)

Solving the equation:
Expanding the equation:
7x + 5 = 4x + 20
Rearranging terms:
7x - 4x = 20 - 5
3x = 15
x = 5

Present age of both:
Son's present age (x) = 5 years
Father's present age (7x) = 7 * 5 = 35 years
Therefore, the present age of the son is 5 years, and the present age of the father is 35 years.
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A father is seven times as old as his son five years from now he will be your times as old as his son .Find the present age of both?
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