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If p(A'UB')=5/6 ,P(A)=1/2,P(B')=2/3 then what is P(AUB)?
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If p(A'UB')=5/6 ,P(A)=1/2,P(B')=2/3 then what is P(AUB)?
Calculation of P(AUB)


  1. Given information:
    • P(A')UB') = 5/6
    • P(A) = 1/2
    • P(B') = 2/3




  2. Finding P(AUB):
    To find P(AUB), we can use the formula:
    P(AUB) = P(A) + P(B) - P(A∩B)


  3. Calculating P(A∩B):
    Since P(A'UB') = 5/6, we can rewrite this as:
    1 - P(AUB) = 5/6
    Therefore, P(AUB) = 1 - 5/6 = 1/6


  4. Substitute values:
    Now, substitute the values of P(A), P(B'), and P(A∩B) into the formula:
    P(AUB) = 1/2 + 1/3 - 1/6
    P(AUB) = 3/6 + 2/6 - 1/6
    P(AUB) = 4/6

    P(AUB) = 2/3


By following these steps, we have calculated that P(AUB) is equal to 2/3.
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If p(A'UB')=5/6 ,P(A)=1/2,P(B')=2/3 then what is P(AUB)?
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