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A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s. If the point of projection is at a height of 12m from the ground then calculate the distance up to which the ball is thrown by the player. (g=10m/s square)?
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A player throws a ball at an angle of 30 up with the horizontal with a...

Given data:

  • Angle of projection (θ): 30°
  • Initial velocity (u): 14 m/s
  • Height of the point of projection (h): 12 m
  • Acceleration due to gravity (g): 10 m/s2


Calculating the horizontal distance:

First, calculate the time of flight using the formula:

Time of flight = 2 * (u * sin(θ)) / g

Time of flight = 2 * (14 * sin(30°)) / 10 = 2 * (14 * 0.5) / 10 = 1.4 seconds

Now, calculate the horizontal distance using the formula:

Horizontal distance = u * cos(θ) * time of flight

Horizontal distance = 14 * cos(30°) * 1.4 = 14 * 0.866 * 1.4 = 17.17 meters

Conclusion:

The player throws the ball at an angle of 30° with the horizontal and a velocity of 14 m/s. The ball travels a horizontal distance of 17.17 meters before hitting the ground. The initial height of the point of projection does not affect the horizontal distance in projectile motion.

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A player throws a ball at an angle of 30 up with the horizontal with a velocity of 14m/s. If the point of projection is at a height of 12m from the ground then calculate the distance up to which the ball is thrown by the player. (g=10m/s square)?
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