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Sum of digits of a two digit number is 10 . if 18 be subtracted from it the digits in resulting number will be equal?
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Sum of digits of a two digit number is 10 . if 18 be subtracted from i...
Explanation:

Given:
Let the two-digit number be represented as 10a + b, where a is the digit in the tens place and b is the digit in the ones place. According to the given condition, a + b = 10.

Subtracting 18 from the number:
When 18 is subtracted from the two-digit number, we get:
(10a + b) - 18 = 10a + b - 18

Breaking down the subtraction:
(10a + b) - 18 = 10a + b - 18
= 10a + b - (10 + 8)
= 10a - 10 + b - 8
= 10(a - 1) + (b - 8)

Equating the digits in the resulting number:
From the above expression, we can see that the resulting number has digits a - 1 and b - 8. To have equal digits in the resulting number, we need a - 1 = b - 8.

Explaining the condition for equal digits:
Since a + b = 10 (given), we can substitute b = 10 - a in the equation a - 1 = b - 8 to get:
a - 1 = (10 - a) - 8
a - 1 = 10 - a - 8
a - 1 = 2 - a
2a = 3
a = 3/2 (which is not possible as a is a digit)

Conclusion:
From the above calculation, we can conclude that when 18 is subtracted from a two-digit number whose sum of digits is 10, the resulting number will not have equal digits.
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Sum of digits of a two digit number is 10 . if 18 be subtracted from it the digits in resulting number will be equal?
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