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Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol) is dissolved in 500 g of water?
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Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapou...
Calculation of Vapour Pressure of Aqueous Solution
Given Data:
- Temperature (T) = 293 K
- Vapour pressure of pure water (P°) = 17.536 mm Hg
- Mass of glucose (m₁) = 20 g
- Mass of water (m₂) = 500 g
- Molar mass of glucose (M) = 180 g/mol
Step 1: Calculate the mole fraction of glucose (χ₁)
- Number of moles of glucose (n₁) = m₁/M
- Number of moles of water (n₂) = m₂/18 (since Molar mass of water = 18 g/mol)
- Total moles of solute and solvent = n₁ + n₂
- Mole fraction of glucose (χ₁) = n₁/(n₁ + n₂)
Step 2: Calculate the vapour pressure of the solution using Raoult's Law
- Vapour pressure of the solution (P) = χ₁ * P°
Step 3: Substitute the values to find the vapour pressure of the solution
- Substitute the calculated mole fraction of glucose into the Raoult's Law equation:
- P = χ₁ * P°
Step 4: Solve for the vapour pressure of the solution
- Calculate the mole fraction of glucose (as calculated in Step 1)
- Substitute the values of P° and χ₁ into the equation from Step 2 to find the vapour pressure of the solution.
By following these steps, you can calculate the vapour pressure of the aqueous solution when 20 g of glucose is dissolved in 500 g of water at 293 K. This process helps in understanding the relationship between solute concentration and vapour pressure in a solution.
Given Data:
- Temperature (T) = 293 K
- Vapour pressure of pure water (P°) = 17.536 mm Hg
- Mass of glucose (m₁) = 20 g
- Mass of water (m₂) = 500 g
- Molar mass of glucose (M) = 180 g/mol
Step 1: Calculate the mole fraction of glucose (χ₁)
- Number of moles of glucose (n₁) = m₁/M
- Number of moles of water (n₂) = m₂/18 (since Molar mass of water = 18 g/mol)
- Total moles of solute and solvent = n₁ + n₂
- Mole fraction of glucose (χ₁) = n₁/(n₁ + n₂)
Step 2: Calculate the vapour pressure of the solution using Raoult's Law
- Vapour pressure of the solution (P) = χ₁ * P°
Step 3: Substitute the values to find the vapour pressure of the solution
- Substitute the calculated mole fraction of glucose into the Raoult's Law equation:
- P = χ₁ * P°
Step 4: Solve for the vapour pressure of the solution
- Calculate the mole fraction of glucose (as calculated in Step 1)
- Substitute the values of P° and χ₁ into the equation from Step 2 to find the vapour pressure of the solution.
By following these steps, you can calculate the vapour pressure of the aqueous solution when 20 g of glucose is dissolved in 500 g of water at 293 K. This process helps in understanding the relationship between solute concentration and vapour pressure in a solution.
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Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol) is dissolved in 500 g of water?
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Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol) is dissolved in 500 g of water? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol) is dissolved in 500 g of water? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol) is dissolved in 500 g of water?.
Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol) is dissolved in 500 g of water? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol) is dissolved in 500 g of water? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vapour pressure of water at 293 K is 17:536 mm Hg. Calculate the vapour pressure of aqueous solution when 20 g of glucose (Molar mass = 180 g mol) is dissolved in 500 g of water?.
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