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Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of water such that it's osmotic pressure is 0.75 atmosphere at 27 degree Celsius when CaCl2 is 40 % dissociated?
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Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of wate...
Calculation of Osmotic Pressure of CaCl2
Given data:
- Volume of water (V) = 2.5 L
- Osmotic pressure (π) = 0.75 atm
- Temperature (T) = 27°C
- Percent dissociation of CaCl2 (α) = 40%
Formula to calculate osmotic pressure:
π = i * MRT
where,
π = osmotic pressure
i = van't Hoff factor
M = molarity of solute
R = gas constant
T = temperature in Kelvin
Calculating van't Hoff factor (i):
For CaCl2, it dissociates into 3 ions (Ca2+ and 2Cl-)
i = 1 + (n-1)α
i = 1 + (3-1)*0.4
i = 1.8
Calculating molarity of CaCl2:
Molarity = moles of solute / volume of solution
Assuming 1 mol of CaCl2 is dissolved,
Molarity = 1 mol / 2.5 L
Molarity = 0.4 M
Converting temperature to Kelvin:
T(K) = 27°C + 273
T = 300 K
Calculating osmotic pressure:
π = 1.8 * 0.4 M * 0.0821 atm L / mol K * 300 K
π = 0.8664 atm
Therefore, the osmotic pressure of CaCl2 solution is 0.8664 atm.
Given data:
- Volume of water (V) = 2.5 L
- Osmotic pressure (π) = 0.75 atm
- Temperature (T) = 27°C
- Percent dissociation of CaCl2 (α) = 40%
Formula to calculate osmotic pressure:
π = i * MRT
where,
π = osmotic pressure
i = van't Hoff factor
M = molarity of solute
R = gas constant
T = temperature in Kelvin
Calculating van't Hoff factor (i):
For CaCl2, it dissociates into 3 ions (Ca2+ and 2Cl-)
i = 1 + (n-1)α
i = 1 + (3-1)*0.4
i = 1.8
Calculating molarity of CaCl2:
Molarity = moles of solute / volume of solution
Assuming 1 mol of CaCl2 is dissolved,
Molarity = 1 mol / 2.5 L
Molarity = 0.4 M
Converting temperature to Kelvin:
T(K) = 27°C + 273
T = 300 K
Calculating osmotic pressure:
π = 1.8 * 0.4 M * 0.0821 atm L / mol K * 300 K
π = 0.8664 atm
Therefore, the osmotic pressure of CaCl2 solution is 0.8664 atm.
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Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of water such that it's osmotic pressure is 0.75 atmosphere at 27 degree Celsius when CaCl2 is 40 % dissociated?
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Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of water such that it's osmotic pressure is 0.75 atmosphere at 27 degree Celsius when CaCl2 is 40 % dissociated? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of water such that it's osmotic pressure is 0.75 atmosphere at 27 degree Celsius when CaCl2 is 40 % dissociated? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of water such that it's osmotic pressure is 0.75 atmosphere at 27 degree Celsius when CaCl2 is 40 % dissociated?.
Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of water such that it's osmotic pressure is 0.75 atmosphere at 27 degree Celsius when CaCl2 is 40 % dissociated? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of water such that it's osmotic pressure is 0.75 atmosphere at 27 degree Celsius when CaCl2 is 40 % dissociated? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the osmotic pressure of CaCl2 dissolved in 2.5 litre of water such that it's osmotic pressure is 0.75 atmosphere at 27 degree Celsius when CaCl2 is 40 % dissociated?.
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