Particle have inital velocity 10m/s moves with const acceleration after turning 300 m distance its velocity becomes 20 m/sec find out time Interval?

Question

Answer

Given data:
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 20 m/s
- Distance (s) = 300 m

Find out:
Time interval taken by the particle to reach final velocity.

Calculating time interval:
- Using the equation of motion: $v^2 = u^2 + 2as$
- Substituting the given values, we get: $20^2 = 10^2 + 2a(300)$
- Solving for acceleration 'a', we get: $a = \frac{(20^2 - 10^2)}{2(300)} = \frac{300}{600} = 0.5 m/s^2$
- Now, using the equation of motion: $v = u + at$
- Substituting the values of 'u', 'v', and 'a', we get: $20 = 10 + 0.5t$
- Solving for time interval 't', we get: \(t = \frac{(20 - 10)}{0.5} = \frac{10}{0.5} = 20 seconds

Therefore, the time interval taken by the particle to reach a final velocity of 20 m/s is 20 seconds.

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