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A tower is 100√3 high find the angle of elevation if its top from point is 100 meter away from its foot?
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A tower is 100√3 high find the angle of elevation if its top from poin...


Given:
Height of tower, AB = 100√3 m
Distance from the foot of the tower to the point, BC = 100 m


Find:
Angle of elevation of the top of the tower from the point C


Explanation:


Step 1: Draw a diagram
Draw a right-angled triangle ABC where:
- A is the top of the tower
- B is the foot of the tower
- C is the point from where the angle of elevation is to be measured


Step 2: Use trigonometry
In triangle ABC, we can use trigonometry to find the angle of elevation.
tan(angle of elevation) = Opposite/Adjacent
tan(angle of elevation) = AB/BC
tan(angle of elevation) = (100√3)/100
tan(angle of elevation) = √3
angle of elevation = tan^(-1)(√3)
angle of elevation ≈ 60 degrees


Step 3: Conclusion
The angle of elevation of the top of the tower from the point is approximately 60 degrees.
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A tower is 100√3 high find the angle of elevation if its top from point is 100 meter away from its foot?
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