A student's mark was wrongly entered as 83 instead of 63. Due to that ...
Let the total number of students = x
The average marks increased by
due to an increase of 83 - 63 = 20 marks.
But total increase in the marks =
Hence we can write as
This question is part of UPSC exam. View all Quant courses
A student's mark was wrongly entered as 83 instead of 63. Due to that ...
Let the sum be x then n be no of students and a be avg then proceed its an easy task
A student's mark was wrongly entered as 83 instead of 63. Due to that ...
To solve this problem, let's first analyze the given information:
- A student's mark was wrongly entered as 83 instead of 63.
- Due to this error, the average marks for the class got increased by half 1/2.
Let's assume there are 'n' students in the class.
Calculating the initial average:
- The sum of all the marks in the class before the error occurred would be (n * previous average).
- Since the average is the sum of all the marks divided by the number of students, the previous average can be written as (sum of all marks / n).
Calculating the final average:
- If the student's mark was wrongly entered as 83 instead of 63, it means that the sum of all marks was increased by 83 - 63 = 20.
- The new sum of all marks in the class after the error occurred would be (sum of all marks + 20).
- The number of students remains the same, i.e., 'n'.
Now, let's equate the initial and final average:
(previous average) + 1/2 = (new sum of all marks) / n
Breaking down the equation:
(sum of all marks / n) + 1/2 = (sum of all marks + 20) / n
Multiplying both sides of the equation by 'n':
(sum of all marks) + (1/2 * n) = (sum of all marks) + 20
Simplifying the equation:
1/2 * n = 20
Multiplying both sides of the equation by 2:
n = 40
Therefore, the number of students in the class is 40 (option B).