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The nth term of a sequence is given by Tn=4Tn-1-3. if the twice the third term is 5 times the second term, fine the first three term of the sequence?
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The nth term of a sequence is given by Tn=4Tn-1-3. if the twice the th...
Given Information:
The nth term of the sequence is given by Tn = 4Tn-1 - 3.

Given Condition:
Twice the third term is equal to 5 times the second term.

Solution:

Let's find the first three terms of the sequence.

First Term (T1):
T1 = 4T0 - 3
T1 = 4(0) - 3
T1 = -3

Second Term (T2):
T2 = 4T1 - 3
T2 = 4(-3) - 3
T2 = -15

Third Term (T3):
T3 = 4T2 - 3
T3 = 4(-15) - 3
T3 = -63

Given Condition:
2 * T3 = 5 * T2
2 * (-63) = 5 * (-15)
-126 = -75

Conclusion:
The first three terms of the sequence are T1 = -3, T2 = -15, and T3 = -63. The condition given in the problem is not satisfied, as -126 does not equal -75.
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The nth term of a sequence is given by Tn=4Tn-1-3. if the twice the third term is 5 times the second term, fine the first three term of the sequence?
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