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If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?
- a)10-3
- b)10-4
- c)10-5
- d)10-8
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility ...
Explanation: For the salt AxBy, (AxBy = xAy+ + yBx+), the solubility of a sparingly soluble salt is given by xx.yy.sx+y. Ksp = xx.yy.sx+y, where x = 2 and y = 3; Ksp = 108S5 = 1 x 10-25. S = 10-5. The solubility of the salt is given by 10-5.
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Most Upvoted Answer
If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility ...
Explanation:
Solubility product (Ksp) definition:
- Ksp is the equilibrium constant for a solid that dissolves in water to form a saturated solution.
- It is the product of the concentrations of the ions in the solution, each raised to the power of the coefficient in the balanced chemical equation.
Given:
- Ksp of salt A2B3 = 1 x 10^-25
Formula:
- For a salt A2B3, the dissociation is A2B3(s) ⇌ 2A^3+ + 3B^2-
- Ksp = [A^3+]^2[B^2-]^3
Solubility calculation:
- Let x be the solubility of A2B3 in moles per liter.
- At equilibrium, the concentrations of A^3+ and B^2- ions will be 2x and 3x respectively.
- Substituting these values in the Ksp expression, we get:
- Ksp = (2x)^2(3x)^3
- 1 x 10^-25 = 108x^5
- x^5 = 10^-26
- x = 10^-26^(1/5)
- x = 10^-5
Therefore, the solubility of the salt A2B3 is 10^-5, which corresponds to option 'c'.
Solubility product (Ksp) definition:
- Ksp is the equilibrium constant for a solid that dissolves in water to form a saturated solution.
- It is the product of the concentrations of the ions in the solution, each raised to the power of the coefficient in the balanced chemical equation.
Given:
- Ksp of salt A2B3 = 1 x 10^-25
Formula:
- For a salt A2B3, the dissociation is A2B3(s) ⇌ 2A^3+ + 3B^2-
- Ksp = [A^3+]^2[B^2-]^3
Solubility calculation:
- Let x be the solubility of A2B3 in moles per liter.
- At equilibrium, the concentrations of A^3+ and B^2- ions will be 2x and 3x respectively.
- Substituting these values in the Ksp expression, we get:
- Ksp = (2x)^2(3x)^3
- 1 x 10^-25 = 108x^5
- x^5 = 10^-26
- x = 10^-26^(1/5)
- x = 10^-5
Therefore, the solubility of the salt A2B3 is 10^-5, which corresponds to option 'c'.
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If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?a)10-3b)10-4c)10-5d)10-8Correct answer is option 'C'. Can you explain this answer?
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