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If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?
- a)10-3
- b)10-4
- c)10-5
- d)10-8
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility ...
Explanation: For the salt AxBy, (AxBy = xAy+ + yBx+), the solubility of a sparingly soluble salt is given by xx.yy.sx+y. Ksp = xx.yy.sx+y, where x = 2 and y = 3; Ksp = 108S5 = 1 x 10-25. S = 10-5. The solubility of the salt is given by 10-5.
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Most Upvoted Answer
If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility ...
Explanation:
Solubility product (Ksp) definition:
- Ksp is the equilibrium constant for a solid that dissolves in water to form a saturated solution.
- It is the product of the concentrations of the ions in the solution, each raised to the power of the coefficient in the balanced chemical equation.
Given:
- Ksp of salt A2B3 = 1 x 10^-25
Formula:
- For a salt A2B3, the dissociation is A2B3(s) ⇌ 2A^3+ + 3B^2-
- Ksp = [A^3+]^2[B^2-]^3
Solubility calculation:
- Let x be the solubility of A2B3 in moles per liter.
- At equilibrium, the concentrations of A^3+ and B^2- ions will be 2x and 3x respectively.
- Substituting these values in the Ksp expression, we get:
- Ksp = (2x)^2(3x)^3
- 1 x 10^-25 = 108x^5
- x^5 = 10^-26
- x = 10^-26^(1/5)
- x = 10^-5
Therefore, the solubility of the salt A2B3 is 10^-5, which corresponds to option 'c'.
Solubility product (Ksp) definition:
- Ksp is the equilibrium constant for a solid that dissolves in water to form a saturated solution.
- It is the product of the concentrations of the ions in the solution, each raised to the power of the coefficient in the balanced chemical equation.
Given:
- Ksp of salt A2B3 = 1 x 10^-25
Formula:
- For a salt A2B3, the dissociation is A2B3(s) ⇌ 2A^3+ + 3B^2-
- Ksp = [A^3+]^2[B^2-]^3
Solubility calculation:
- Let x be the solubility of A2B3 in moles per liter.
- At equilibrium, the concentrations of A^3+ and B^2- ions will be 2x and 3x respectively.
- Substituting these values in the Ksp expression, we get:
- Ksp = (2x)^2(3x)^3
- 1 x 10^-25 = 108x^5
- x^5 = 10^-26
- x = 10^-26^(1/5)
- x = 10^-5
Therefore, the solubility of the salt A2B3 is 10^-5, which corresponds to option 'c'.
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If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?a)10-3b)10-4c)10-5d)10-8Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?a)10-3b)10-4c)10-5d)10-8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?a)10-3b)10-4c)10-5d)10-8Correct answer is option 'C'. Can you explain this answer?.
If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?a)10-3b)10-4c)10-5d)10-8Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?a)10-3b)10-4c)10-5d)10-8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If Ksp of a salt A2B3 is given by 1 x 10-25. Then find the solubility of the salt?a)10-3b)10-4c)10-5d)10-8Correct answer is option 'C'. Can you explain this answer?.
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