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The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segment

a. AB
b. BC
c. CD
d. equal for all parts?

a. AB
b. BC
c. CD
d. equal for all parts?
Most Upvoted Answer
The velocity time (v - t) graph of a moving particle is shown in Figur...
- **Acceleration Analysis**
Acceleration is the rate of change of velocity with respect to time. To determine where the acceleration is maximum on the v-t graph, we need to look at which segment has the steepest slope.
- **Segment AB**
In segment AB, the velocity is increasing at a constant rate, resulting in a constant positive acceleration. The slope of the graph in this segment is constant, indicating a steady acceleration.
- **Segment BC**
In segment BC, the velocity is constant, meaning there is no change in velocity and therefore no acceleration. The slope of the graph is zero, signifying zero acceleration.
- **Segment CD**
In segment CD, the velocity is decreasing at a constant rate, resulting in a constant negative acceleration. The slope of the graph in this segment is constant, indicating a steady deceleration.
- **Conclusion**
From the analysis of the v-t graph, we can see that the acceleration is maximum in segment **a (AB)** where the slope is the steepest. This is because the particle is experiencing a constant positive acceleration in this segment. Therefore, the correct answer is **a. AB**.
Acceleration is the rate of change of velocity with respect to time. To determine where the acceleration is maximum on the v-t graph, we need to look at which segment has the steepest slope.
- **Segment AB**
In segment AB, the velocity is increasing at a constant rate, resulting in a constant positive acceleration. The slope of the graph in this segment is constant, indicating a steady acceleration.
- **Segment BC**
In segment BC, the velocity is constant, meaning there is no change in velocity and therefore no acceleration. The slope of the graph is zero, signifying zero acceleration.
- **Segment CD**
In segment CD, the velocity is decreasing at a constant rate, resulting in a constant negative acceleration. The slope of the graph in this segment is constant, indicating a steady deceleration.
- **Conclusion**
From the analysis of the v-t graph, we can see that the acceleration is maximum in segment **a (AB)** where the slope is the steepest. This is because the particle is experiencing a constant positive acceleration in this segment. Therefore, the correct answer is **a. AB**.
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The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segmenta. ABb. BCc. CDd. equal for all parts?
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The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segmenta. ABb. BCc. CDd. equal for all parts? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segmenta. ABb. BCc. CDd. equal for all parts? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segmenta. ABb. BCc. CDd. equal for all parts?.
The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segmenta. ABb. BCc. CDd. equal for all parts? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segmenta. ABb. BCc. CDd. equal for all parts? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segmenta. ABb. BCc. CDd. equal for all parts?.
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