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If alpha and beta zeros of quadratic polynomial p of X equals to 6xsquare + X - 1 then find the value of Alpha / beta + beta / alpha + 2 into 1 upon alpha + 1 upon beta + 3 alpha beta?
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If alpha and beta zeros of quadratic polynomial p of X equals to 6xsqu...
- **Given Information**
Given quadratic polynomial p(x) = 6x^2 + x - 1 with zeros alpha and beta.
- **Finding the Value**
We are required to find the value of the expression:
\[ \frac{\alpha}{\beta} + \frac{\beta}{\alpha} + 2\left(\frac{1}{\alpha} + \frac{1}{\beta}\right) + 3\alpha\beta \]
- **Solution**
1. We know that the sum of zeros of a quadratic polynomial is given by:
\[ \alpha + \beta = -\frac{b}{a} \]
In this case, a = 6 and b = 1, so:
\[ \alpha + \beta = -\frac{1}{6} \]
2. Similarly, the product of zeros is given by:
\[ \alpha\beta = \frac{c}{a} \]
In this case, a = 6 and c = -1, so:
\[ \alpha\beta = -\frac{1}{6} \]
3. Substituting the values of alpha, beta, alpha + beta, and alpha*beta into the expression, we get:
\[ \frac{\alpha}{\beta} + \frac{\beta}{\alpha} + 2\left(\frac{1}{\alpha} + \frac{1}{\beta}\right) + 3\alpha\beta \]
\[ = \frac{-1/6}{-1/6} + \frac{-1/6}{-1/6} + 2\left(\frac{1}{-1/6} + \frac{1}{-1/6}\right) + 3*(-1/6) \]
\[ = 1 + 1 + 2*(-6) + (-1/2) \]
\[ = 2 - 12 - 1/2 \]
\[ = -10.5 \]
Therefore, the value of the expression is -10.5.
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If alpha and beta zeros of quadratic polynomial p of X equals to 6xsquare + X - 1 then find the value of Alpha / beta + beta / alpha + 2 into 1 upon alpha + 1 upon beta + 3 alpha beta?
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