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Diwali rocket is ejecting 50 g of gases at a velocity of 400 m/s. The acceleration force on the
rocket will be?
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Diwali rocket is ejecting 50 g of gases at a velocity of 400 m/s. The ...
Calculation of Acceleration Force on Diwali Rocket
Acceleration force on the Diwali rocket can be calculated using Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given Data:
- Mass of gases ejected (m): 50 g = 0.05 kg
- Velocity of gases ejected (v): 400 m/s

Step 1: Calculation of Acceleration
Acceleration (a) can be calculated using the formula:
a = v/t
where,
v = velocity of gases ejected = 400 m/s
t = time taken for ejection of gases (assumed to be 1 second)
Therefore, acceleration (a) = 400 m/s / 1 s = 400 m/s²

Step 2: Calculation of Acceleration Force
Acceleration force (F) can be calculated using the formula:
F = m * a
where,
m = mass of gases ejected = 0.05 kg
a = acceleration = 400 m/s²
Therefore, acceleration force (F) = 0.05 kg * 400 m/s² = 20 N
Therefore, the acceleration force on the Diwali rocket will be 20 Newtons.
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Diwali rocket is ejecting 50 g of gases at a velocity of 400 m/s. The acceleration force on therocket will be?
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