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If R is the radius of the earth and g is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:
- a)πg/12RG
- b)3g/4πRG
- c)4πG/3gR
- d)3πR/4gG
Correct answer is option 'B'. Can you explain this answer?
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If R is the radius of the earth and g is the acceleration due to gravi...
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If R is the radius of the earth and g is the acceleration due to gravi...
Explanation:
- Given:
- Radius of the earth, R
- Acceleration due to gravity on the earth surface, g
- Formula:
- Mean density of the earth, ρ = 3M/(4πR^3), where M is the mass of the earth
- Derivation:
- From the formula for gravitational force, F = GMm/R^2, where M is the mass of the earth, m is the mass of the object, and G is the gravitational constant.
- From the formula for acceleration due to gravity, g = GM/R^2
- By substituting the value of M in terms of density and volume, we get M = 4/3 * π * R^3 * ρ
- Substituting the value of M in the formula for acceleration due to gravity, g = (4/3) * π * G * ρ * R
- Solving for ρ, we get ρ = 3g / (4πGR)
- Therefore, the mean density of the earth is:
- 3g / (4πGR)
Therefore, the correct answer is option B (3?R^4g/G).
- Given:
- Radius of the earth, R
- Acceleration due to gravity on the earth surface, g
- Formula:
- Mean density of the earth, ρ = 3M/(4πR^3), where M is the mass of the earth
- Derivation:
- From the formula for gravitational force, F = GMm/R^2, where M is the mass of the earth, m is the mass of the object, and G is the gravitational constant.
- From the formula for acceleration due to gravity, g = GM/R^2
- By substituting the value of M in terms of density and volume, we get M = 4/3 * π * R^3 * ρ
- Substituting the value of M in the formula for acceleration due to gravity, g = (4/3) * π * G * ρ * R
- Solving for ρ, we get ρ = 3g / (4πGR)
- Therefore, the mean density of the earth is:
- 3g / (4πGR)
Therefore, the correct answer is option B (3?R^4g/G).
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If R is the radius of the earth and g is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:a)πg/12RGb)3g/4πRGc)4πG/3gRd)3πR/4gGCorrect answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If R is the radius of the earth and g is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:a)πg/12RGb)3g/4πRGc)4πG/3gRd)3πR/4gGCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If R is the radius of the earth and g is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:a)πg/12RGb)3g/4πRGc)4πG/3gRd)3πR/4gGCorrect answer is option 'B'. Can you explain this answer?.
If R is the radius of the earth and g is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:a)πg/12RGb)3g/4πRGc)4πG/3gRd)3πR/4gGCorrect answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If R is the radius of the earth and g is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:a)πg/12RGb)3g/4πRGc)4πG/3gRd)3πR/4gGCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If R is the radius of the earth and g is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:a)πg/12RGb)3g/4πRGc)4πG/3gRd)3πR/4gGCorrect answer is option 'B'. Can you explain this answer?.
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