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56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia that are mine and calculate the mass of ammonia?
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56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia ...
Given Data:
- Mass of nitrogen (N₂) = 56 g
- Mass of hydrogen (H₂) = 10 g
Calculating the molar mass of N₂ and H₂:
- Molar mass of N₂ = 2(14.01) = 28.02 g/mol
- Molar mass of H₂ = 2(1.01) = 2.02 g/mol
Calculating the moles of reactants:
- Moles of N₂ = 56 g / 28.02 g/mol = 2 moles
- Moles of H₂ = 10 g / 2.02 g/mol = 4.95 moles (approximately 5 moles)
Stoichiometry of the reaction:
- The balanced equation for the reaction is: N₂ + 3H₂ → 2NH₃
- This means 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃
Limiting reactant:
- From the moles calculated above, it is clear that N₂ is the limiting reactant as it has fewer moles compared to H₂
Calculating the mass of ammonia produced:
- Moles of NH₃ produced will be half of the moles of N₂ consumed, which is 1 mole
- The molar mass of NH₃ is 17.03 g/mol
- Mass of NH₃ produced = 1 mole * 17.03 g/mol = 17.03 g
Therefore, the mass of ammonia produced when 56 g of nitrogen reacts with 10 g of hydrogen is 17.03 grams.
- Mass of nitrogen (N₂) = 56 g
- Mass of hydrogen (H₂) = 10 g
Calculating the molar mass of N₂ and H₂:
- Molar mass of N₂ = 2(14.01) = 28.02 g/mol
- Molar mass of H₂ = 2(1.01) = 2.02 g/mol
Calculating the moles of reactants:
- Moles of N₂ = 56 g / 28.02 g/mol = 2 moles
- Moles of H₂ = 10 g / 2.02 g/mol = 4.95 moles (approximately 5 moles)
Stoichiometry of the reaction:
- The balanced equation for the reaction is: N₂ + 3H₂ → 2NH₃
- This means 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃
Limiting reactant:
- From the moles calculated above, it is clear that N₂ is the limiting reactant as it has fewer moles compared to H₂
Calculating the mass of ammonia produced:
- Moles of NH₃ produced will be half of the moles of N₂ consumed, which is 1 mole
- The molar mass of NH₃ is 17.03 g/mol
- Mass of NH₃ produced = 1 mole * 17.03 g/mol = 17.03 g
Therefore, the mass of ammonia produced when 56 g of nitrogen reacts with 10 g of hydrogen is 17.03 grams.
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56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia that are mine and calculate the mass of ammonia?
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56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia that are mine and calculate the mass of ammonia? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia that are mine and calculate the mass of ammonia? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia that are mine and calculate the mass of ammonia?.
56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia that are mine and calculate the mass of ammonia? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia that are mine and calculate the mass of ammonia? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 56 gram of nitrogen react with 10 gram of hydrogen to produce ammonia that are mine and calculate the mass of ammonia?.
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