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What is the rise in temperature of 10 litres of water when it is heated for 30 minutes by an immersion rod rated 220 volt - 1.5 KW and given that specific heat of water is 4200J/kg'C.?
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What is the rise in temperature of 10 litres of water when it is heate...
Calculation of Temperature Rise in Water
- First, calculate the energy consumed by the immersion rod in 30 minutes:
- Power = 1.5 kW = 1500 W
- Time = 30 minutes = 30 x 60 seconds = 1800 seconds
- Energy = Power x Time = 1500 W x 1800 s = 2700000 J
- Next, calculate the mass of water heated:
- Density of water = 1000 kg/m^3
- Volume = 10 liters = 0.01 m^3
- Mass = Density x Volume = 1000 kg/m^3 x 0.01 m^3 = 10 kg
- Now, use the formula Q = mcΔT, where:
- Q = Energy consumed by the water (2700000 J)
- m = Mass of water (10 kg)
- c = Specific heat of water (4200 J/kg°C)
- ΔT = Temperature rise
- Rearrange the formula to find ΔT:
- ΔT = Q / (mc) = 2700000 J / (10 kg x 4200 J/kg°C) ≈ 64.29°C
Therefore, the temperature of 10 liters of water will rise by approximately 64.29°C when heated for 30 minutes by the immersion rod rated 220V - 1.5kW.
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What is the rise in temperature of 10 litres of water when it is heated for 30 minutes by an immersion rod rated 220 volt - 1.5 KW and given that specific heat of water is 4200J/kg'C.?
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