The pair of linear equations x + y + 10 = 0 and x + y – 7 = 0 ha...
We have a1, a2 the coefficients of x
2,b1 and b2 coefficients of x and c1 and c2 the constant terms.

So,

a1a2=b1b2c1c2which is a case of parallel lines which which never meet. So there are no solutions obtainable for these equations.
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The pair of linear equations x + y + 10 = 0 and x + y – 7 = 0 ha...
We have a1, a2 the coefficients of x
2,b1 and b2 coefficients of x and c1 and c2 the constant terms.

So,

a1a2=b1b2c1c2which is a case of parallel lines which which never meet. So there are no solutions obtainable for these equations.
The pair of linear equations x + y + 10 = 0 and x + y – 7 = 0 ha...
Understanding the Given Equations
The equations provided are:
1. \(x + y + 10 = 0\)
2. \(x + y - 7 = 0\)
To analyze the relationship between these two equations, we can rewrite them in a more familiar form.
Rearranging the Equations
- Equation 1:
\(x + y = -10\)
- Equation 2:
\(x + y = 7\)
Identifying the Nature of Solutions
Both equations represent straight lines in a 2D plane:
- Line 1: All points \((x, y)\) that satisfy \(x + y = -10\).
- Line 2: All points \((x, y)\) that satisfy \(x + y = 7\).
Analyzing the Lines
- Both lines are parallel because they have the same slope (coefficient of \(x\) and \(y\) is 1 in both cases).
- Since they have different y-intercepts (\(-10\) and \(7\)), they will never intersect.
Conclusion
Since the two lines are parallel and do not intersect, they do not share any common points. Therefore, the system of equations has:
- No solutions.
Hence, the correct answer is option 'C'.