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A disc of mass 2kg is kept floating horizontally in air by firing bullets of mass 0.1kg each vertically at it at the rate of 5 per second ,if the bullets rebound with the same speed ,the speed with which these are fired will be :?
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A disc of mass 2kg is kept floating horizontally in air by firing bull...
Understanding the scenario:
A disc of mass 2kg is floating horizontally in air, being kept afloat by bullets of mass 0.1kg fired at it vertically.

Calculating the force required:
The weight of the disc = mass x gravity = 2kg x 9.8m/s² = 19.6N
The force of each bullet = mass x acceleration = 0.1kg x 9.8m/s² = 0.98N
The total force exerted by 5 bullets per second = 5 x 0.98N = 4.9N

Calculating the speed of the bullets:
The bullets are fired vertically and rebound with the same speed, meaning the change in momentum is twice the momentum of the bullet.
Change in momentum = 2 x momentum of bullet = 2 x mass x velocity = 2 x 0.1kg x v
Rate of change of momentum = force exerted = 4.9N
Hence, 2 x 0.1kg x v x 5 = 4.9N
v = 4.9N / (0.1kg x 10) = 4.9m/s
Therefore, the speed at which the bullets need to be fired to keep the disc floating horizontally is 4.9m/s.
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A disc of mass 2kg is kept floating horizontally in air by firing bullets of mass 0.1kg each vertically at it at the rate of 5 per second ,if the bullets rebound with the same speed ,the speed with which these are fired will be :?
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