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A boll of mass 200g is thrown horizontal towards a wall with a speed 20ms and rebound horizontally with a speed 10 find change in momentum?
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A boll of mass 200g is thrown horizontal towards a wall with a speed 2...
Understanding the Problem
To find the change in momentum of the ball, we need to consider its initial and final velocities. The mass of the ball is given as 200g, which we convert to kilograms for standard SI units.
Mass Conversion
- Mass (m) = 200g = 0.2 kg
Initial and Final Velocities
- Initial velocity (u) = 20 m/s (towards the wall)
- Final velocity (v) = -10 m/s (rebound direction opposite to the initial)
Momentum Calculation
Momentum (p) is defined as the product of mass and velocity.
- Initial momentum (p_initial) = m * u = 0.2 kg * 20 m/s = 4 kg·m/s
- Final momentum (p_final) = m * v = 0.2 kg * (-10 m/s) = -2 kg·m/s
Change in Momentum
The change in momentum (Δp) can be calculated as:
- Δp = p_final - p_initial
- Δp = (-2 kg·m/s) - (4 kg·m/s) = -6 kg·m/s
Conclusion
The change in momentum of the ball is -6 kg·m/s. This negative value indicates that the momentum has decreased in the original direction of the throw, reflecting the loss of momentum upon rebounding from the wall. The significance of this result lies in understanding the impact forces and energy transfer during collisions.
To find the change in momentum of the ball, we need to consider its initial and final velocities. The mass of the ball is given as 200g, which we convert to kilograms for standard SI units.
Mass Conversion
- Mass (m) = 200g = 0.2 kg
Initial and Final Velocities
- Initial velocity (u) = 20 m/s (towards the wall)
- Final velocity (v) = -10 m/s (rebound direction opposite to the initial)
Momentum Calculation
Momentum (p) is defined as the product of mass and velocity.
- Initial momentum (p_initial) = m * u = 0.2 kg * 20 m/s = 4 kg·m/s
- Final momentum (p_final) = m * v = 0.2 kg * (-10 m/s) = -2 kg·m/s
Change in Momentum
The change in momentum (Δp) can be calculated as:
- Δp = p_final - p_initial
- Δp = (-2 kg·m/s) - (4 kg·m/s) = -6 kg·m/s
Conclusion
The change in momentum of the ball is -6 kg·m/s. This negative value indicates that the momentum has decreased in the original direction of the throw, reflecting the loss of momentum upon rebounding from the wall. The significance of this result lies in understanding the impact forces and energy transfer during collisions.
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A boll of mass 200g is thrown horizontal towards a wall with a speed 20ms and rebound horizontally with a speed 10 find change in momentum?
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A boll of mass 200g is thrown horizontal towards a wall with a speed 20ms and rebound horizontally with a speed 10 find change in momentum? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A boll of mass 200g is thrown horizontal towards a wall with a speed 20ms and rebound horizontally with a speed 10 find change in momentum? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A boll of mass 200g is thrown horizontal towards a wall with a speed 20ms and rebound horizontally with a speed 10 find change in momentum?.
A boll of mass 200g is thrown horizontal towards a wall with a speed 20ms and rebound horizontally with a speed 10 find change in momentum? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A boll of mass 200g is thrown horizontal towards a wall with a speed 20ms and rebound horizontally with a speed 10 find change in momentum? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A boll of mass 200g is thrown horizontal towards a wall with a speed 20ms and rebound horizontally with a speed 10 find change in momentum?.
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