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Consider the equation 2H2 + O2=2H2O.What mass of water will be produced,if 0.1gm hydrogen is completely reacting with oxygen (atomic mass: H=1,O=16)?
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Consider the equation 2H2 + O2=2H2O.What mass of water will be produce...
Calculating the mass of water produced:
To calculate the mass of water produced when 0.1g of hydrogen reacts with oxygen, we first need to determine the limiting reactant in the reaction.

Step 1: Determine the limiting reactant:
- Calculate the number of moles of hydrogen:
- 0.1g H2 * (1 mol H2 / 2g H2) = 0.05 mol H2
- Calculate the number of moles of oxygen needed for complete reaction:
- From the balanced equation, 2 moles of H2 react with 1 mole of O2
- Therefore, 0.05 mol H2 would require 0.025 mol O2

Step 2: Calculate the mass of water produced:
- From the balanced equation, 2 moles of H2 produce 2 moles of H2O
- Therefore, 0.05 mol H2 would produce 0.05 mol H2O
- Calculate the mass of water produced:
- Mass = number of moles * molar mass
- Mass of water = 0.05 mol * 18 g/mol = 0.9 g
Therefore, when 0.1g of hydrogen reacts with oxygen, the mass of water produced will be 0.9g. This calculation assumes that hydrogen is the limiting reactant, and the reaction goes to completion.
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Consider the equation 2H2 + O2=2H2O.What mass of water will be produced,if 0.1gm hydrogen is completely reacting with oxygen (atomic mass: H=1,O=16)?
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