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Two identical metal balls with charges +2Q and -2Q are separated by some distance , and exert a force F on each other . They are joined by a conducting wire , which is then removed . the force between them will now be?
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Two identical metal balls with charges +2Q and -2Q are separated by so...
Initial Configuration
- Two identical metal balls are charged with +2Q and -2Q.
- They exert a force \( F \) on each other due to their charges.
- The force is attractive because one charge is positive and the other is negative.
Joining by a Conducting Wire
- When the balls are connected by a conducting wire, charge redistribution occurs.
- The +2Q charge and -2Q charge will neutralize each other.
- Each ball will end up with a charge of \( 0 \) (since \( +2Q + (-2Q) = 0 \)).
Removing the Wire
- Once the wire is removed, both balls remain neutral with a charge of \( 0 \).
- There are no net charges on either ball, which means they cannot exert an electrostatic force on each other.
Final Force Between the Balls
- The force between the two balls after removing the wire will be:
- \( F' = 0 \)
- **Reason**: Since both balls are now electrically neutral, there are no attractive or repulsive forces acting between them.
Conclusion
- Initially, the balls experienced a force \( F \) due to their charge difference.
- After connecting them with a conducting wire, they became neutral, leading to a final force of \( 0 \) when the wire was removed.
This demonstrates the principle of charge conservation and the behavior of conductors in electrostatics.
- Two identical metal balls are charged with +2Q and -2Q.
- They exert a force \( F \) on each other due to their charges.
- The force is attractive because one charge is positive and the other is negative.
Joining by a Conducting Wire
- When the balls are connected by a conducting wire, charge redistribution occurs.
- The +2Q charge and -2Q charge will neutralize each other.
- Each ball will end up with a charge of \( 0 \) (since \( +2Q + (-2Q) = 0 \)).
Removing the Wire
- Once the wire is removed, both balls remain neutral with a charge of \( 0 \).
- There are no net charges on either ball, which means they cannot exert an electrostatic force on each other.
Final Force Between the Balls
- The force between the two balls after removing the wire will be:
- \( F' = 0 \)
- **Reason**: Since both balls are now electrically neutral, there are no attractive or repulsive forces acting between them.
Conclusion
- Initially, the balls experienced a force \( F \) due to their charge difference.
- After connecting them with a conducting wire, they became neutral, leading to a final force of \( 0 \) when the wire was removed.
This demonstrates the principle of charge conservation and the behavior of conductors in electrostatics.
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Two identical metal balls with charges +2Q and -2Q are separated by some distance , and exert a force F on each other . They are joined by a conducting wire , which is then removed . the force between them will now be?
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Two identical metal balls with charges +2Q and -2Q are separated by some distance , and exert a force F on each other . They are joined by a conducting wire , which is then removed . the force between them will now be? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Two identical metal balls with charges +2Q and -2Q are separated by some distance , and exert a force F on each other . They are joined by a conducting wire , which is then removed . the force between them will now be? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical metal balls with charges +2Q and -2Q are separated by some distance , and exert a force F on each other . They are joined by a conducting wire , which is then removed . the force between them will now be?.
Two identical metal balls with charges +2Q and -2Q are separated by some distance , and exert a force F on each other . They are joined by a conducting wire , which is then removed . the force between them will now be? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Two identical metal balls with charges +2Q and -2Q are separated by some distance , and exert a force F on each other . They are joined by a conducting wire , which is then removed . the force between them will now be? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical metal balls with charges +2Q and -2Q are separated by some distance , and exert a force F on each other . They are joined by a conducting wire , which is then removed . the force between them will now be?.
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