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A lead bullet specific heat 0.032 is completely stopped when it strikes a target with velocity 300 the heat generated is equally shared by the bullet and the target the rise in temperature is?
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A lead bullet specific heat 0.032 is completely stopped when it strike...
Calculation of Heat Generated
To find the rise in temperature when a lead bullet strikes a target, we first calculate the kinetic energy converted into heat.
- **Given Data:**
- Specific heat of lead, \( c = 0.032 \, \text{J/g°C} \)
- Velocity of the bullet, \( v = 300 \, \text{m/s} \)
- Mass of the bullet, \( m \) (assumed to be 1 g for simplicity)
- **Kinetic Energy (KE):**
\[
KE = \frac{1}{2} mv^2 = \frac{1}{2} (1 \, \text{g}) (300 \, \text{m/s})^2 = 45000 \, \text{J}
\]
Heat Distribution
The heat generated is equally shared between the bullet and the target.
- **Heat absorbed by the bullet:**
\[
Q_b = \frac{KE}{2} = \frac{45000 \, \text{J}}{2} = 22500 \, \text{J}
\]
Temperature Rise Calculation
Using the specific heat formula, we can find the rise in temperature (\( \Delta T \)) for the bullet.
- **Formula:**
\[
Q = mc\Delta T
\]
- **Solving for \( \Delta T \):**
\[
22500 \, \text{J} = (1 \, \text{g})(0.032 \, \text{J/g°C})\Delta T
\]
- **Rearranging:**
\[
\Delta T = \frac{22500 \, \text{J}}{0.032 \, \text{J/g°C}} = 703125 \, \text{°C}
\]
Conclusion
The rise in temperature of the lead bullet upon impact is approximately **703125 °C**. This significant increase indicates the intense heat generated during the collision.
To find the rise in temperature when a lead bullet strikes a target, we first calculate the kinetic energy converted into heat.
- **Given Data:**
- Specific heat of lead, \( c = 0.032 \, \text{J/g°C} \)
- Velocity of the bullet, \( v = 300 \, \text{m/s} \)
- Mass of the bullet, \( m \) (assumed to be 1 g for simplicity)
- **Kinetic Energy (KE):**
\[
KE = \frac{1}{2} mv^2 = \frac{1}{2} (1 \, \text{g}) (300 \, \text{m/s})^2 = 45000 \, \text{J}
\]
Heat Distribution
The heat generated is equally shared between the bullet and the target.
- **Heat absorbed by the bullet:**
\[
Q_b = \frac{KE}{2} = \frac{45000 \, \text{J}}{2} = 22500 \, \text{J}
\]
Temperature Rise Calculation
Using the specific heat formula, we can find the rise in temperature (\( \Delta T \)) for the bullet.
- **Formula:**
\[
Q = mc\Delta T
\]
- **Solving for \( \Delta T \):**
\[
22500 \, \text{J} = (1 \, \text{g})(0.032 \, \text{J/g°C})\Delta T
\]
- **Rearranging:**
\[
\Delta T = \frac{22500 \, \text{J}}{0.032 \, \text{J/g°C}} = 703125 \, \text{°C}
\]
Conclusion
The rise in temperature of the lead bullet upon impact is approximately **703125 °C**. This significant increase indicates the intense heat generated during the collision.
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A lead bullet specific heat 0.032 is completely stopped when it strikes a target with velocity 300 the heat generated is equally shared by the bullet and the target the rise in temperature is?
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A lead bullet specific heat 0.032 is completely stopped when it strikes a target with velocity 300 the heat generated is equally shared by the bullet and the target the rise in temperature is? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A lead bullet specific heat 0.032 is completely stopped when it strikes a target with velocity 300 the heat generated is equally shared by the bullet and the target the rise in temperature is? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A lead bullet specific heat 0.032 is completely stopped when it strikes a target with velocity 300 the heat generated is equally shared by the bullet and the target the rise in temperature is?.
A lead bullet specific heat 0.032 is completely stopped when it strikes a target with velocity 300 the heat generated is equally shared by the bullet and the target the rise in temperature is? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A lead bullet specific heat 0.032 is completely stopped when it strikes a target with velocity 300 the heat generated is equally shared by the bullet and the target the rise in temperature is? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A lead bullet specific heat 0.032 is completely stopped when it strikes a target with velocity 300 the heat generated is equally shared by the bullet and the target the rise in temperature is?.
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