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A car moving with velocity of 10m\s can be stopped by the application of a constant force F in a distance of 20m . if the velocity of a car is 30m\s . it can be stopped by this force in?
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A car moving with velocity of 10m\s can be stopped by the application ...
Understanding the Scenario
When a car is moving and needs to be stopped, it is influenced by a constant force F. The stopping distance is determined by the initial velocity of the car and the force applied.
Given Data
- Initial velocity (v1) = 10 m/s
- Stopping distance (d1) = 20 m
- Initial velocity (v2) = 30 m/s
Deceleration Calculation
Using the equation of motion:
- For the first scenario, we can use the formula:
d = (v^2 - u^2) / (2a)
Where:
- d = stopping distance
- v = final velocity (0 m/s when stopped)
- u = initial velocity
- a = deceleration
Rearranging gives us the deceleration (a) from the first scenario:
- a = (v1^2) / (2 * d1) = (10^2) / (2 * 20) = 2.5 m/s²
Applying the Same Force
Now, we apply the same force to stop the car moving at 30 m/s. Using the same formula:
- For the second scenario, we need to find d2 where:
a = (v2^2) / (2 * d2)
Substituting the values:
- d2 = (v2^2) / (2 * a) = (30^2) / (2 * 2.5) = 180 m
Conclusion
Therefore, the car moving at 30 m/s can be stopped by the same force in a distance of:
- 180 meters.
This illustrates how increased velocity significantly impacts the stopping distance due to the square relationship between velocity and stopping distance.
When a car is moving and needs to be stopped, it is influenced by a constant force F. The stopping distance is determined by the initial velocity of the car and the force applied.
Given Data
- Initial velocity (v1) = 10 m/s
- Stopping distance (d1) = 20 m
- Initial velocity (v2) = 30 m/s
Deceleration Calculation
Using the equation of motion:
- For the first scenario, we can use the formula:
d = (v^2 - u^2) / (2a)
Where:
- d = stopping distance
- v = final velocity (0 m/s when stopped)
- u = initial velocity
- a = deceleration
Rearranging gives us the deceleration (a) from the first scenario:
- a = (v1^2) / (2 * d1) = (10^2) / (2 * 20) = 2.5 m/s²
Applying the Same Force
Now, we apply the same force to stop the car moving at 30 m/s. Using the same formula:
- For the second scenario, we need to find d2 where:
a = (v2^2) / (2 * d2)
Substituting the values:
- d2 = (v2^2) / (2 * a) = (30^2) / (2 * 2.5) = 180 m
Conclusion
Therefore, the car moving at 30 m/s can be stopped by the same force in a distance of:
- 180 meters.
This illustrates how increased velocity significantly impacts the stopping distance due to the square relationship between velocity and stopping distance.
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A car moving with velocity of 10m\s can be stopped by the application of a constant force F in a distance of 20m . if the velocity of a car is 30m\s . it can be stopped by this force in?
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A car moving with velocity of 10m\s can be stopped by the application of a constant force F in a distance of 20m . if the velocity of a car is 30m\s . it can be stopped by this force in? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A car moving with velocity of 10m\s can be stopped by the application of a constant force F in a distance of 20m . if the velocity of a car is 30m\s . it can be stopped by this force in? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car moving with velocity of 10m\s can be stopped by the application of a constant force F in a distance of 20m . if the velocity of a car is 30m\s . it can be stopped by this force in?.
A car moving with velocity of 10m\s can be stopped by the application of a constant force F in a distance of 20m . if the velocity of a car is 30m\s . it can be stopped by this force in? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A car moving with velocity of 10m\s can be stopped by the application of a constant force F in a distance of 20m . if the velocity of a car is 30m\s . it can be stopped by this force in? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car moving with velocity of 10m\s can be stopped by the application of a constant force F in a distance of 20m . if the velocity of a car is 30m\s . it can be stopped by this force in?.
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