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A bullet of mass 20g moving with a velocity 20m/s enters a wooden block after a distance 10cm. what is average resistance force exerted by the bullet?
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A bullet of mass 20g moving with a velocity 20m/s enters a wooden bloc...
Introduction
To calculate the average resistance force exerted by the bullet as it penetrates the wooden block, we can use the concepts of momentum and work-energy principle.
Given Data
- Mass of the bullet (m) = 20 g = 0.02 kg
- Initial velocity of the bullet (u) = 20 m/s
- Distance penetrated in the block (d) = 10 cm = 0.1 m
Calculating Initial Momentum
- Initial momentum (p) = m × u
- p = 0.02 kg × 20 m/s = 0.4 kg·m/s
Final Momentum
- When the bullet comes to a stop inside the wooden block, its final momentum is 0 kg·m/s.
Change in Momentum
- Change in momentum = Final momentum - Initial momentum
- Change in momentum = 0 - 0.4 = -0.4 kg·m/s
Calculating Average Resistance Force
Using the work-energy principle, the work done by the resistance force (F) is equal to the change in kinetic energy.
- Work done (W) = F × d
- Change in kinetic energy (ΔKE) = 0 - (1/2) × m × u²
- ΔKE = 0 - (1/2) × 0.02 kg × (20 m/s)²
- ΔKE = -4 J
Setting work done equal to the change in kinetic energy:
- F × 0.1 m = -4 J
- F = -4 J / 0.1 m = -40 N
Conclusion
The average resistance force exerted by the bullet as it penetrates the wooden block is 40 N in the opposite direction to the bullet's motion.
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A bullet of mass 20g moving with a velocity 20m/s enters a wooden block after a distance 10cm. what is average resistance force exerted by the bullet?
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