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A bullet of mass 4gm has fixed mass with a velocity of 50m/s can enter a wall upto a depth of 10cm ,how much will be the average resistance offered by the wall?
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A bullet of mass 4gm has fixed mass with a velocity of 50m/s can enter...
Introduction
To determine the average resistance offered by the wall against the bullet, we can use the principles of physics involving momentum and work done.
Given Data
- Mass of the bullet (m) = 4 g = 0.004 kg
- Initial velocity (u) = 50 m/s
- Depth of penetration (d) = 10 cm = 0.1 m
Calculating Initial Momentum
The initial momentum (p) of the bullet can be calculated using the formula:
p = m × u

p = 0.004 kg × 50 m/s = 0.2 kg·m/s

Calculating Work Done Against Resistance
The work done (W) by the bullet to penetrate the wall is equal to the force (F) exerted by the wall times the distance (d) the bullet penetrates:
W = F × d

Since the bullet comes to rest, all its initial kinetic energy is converted into work done against the wall.
Calculating Initial Kinetic Energy
The initial kinetic energy (KE) of the bullet is given by:
KE = 0.5 × m × u²

KE = 0.5 × 0.004 kg × (50 m/s)² = 5 J

Average Resistance Force
The average resistance force (F) can then be found using the work-energy principle:
W = KE

Hence,
F × d = KE

Substituting the values:
F × 0.1 m = 5 J

Solving for F:
F = 5 J / 0.1 m = 50 N

Conclusion
The average resistance offered by the wall to the bullet is 50 N. This calculation illustrates how energy transformations and forces play a critical role in understanding ballistic impacts.
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A bullet of mass 4gm has fixed mass with a velocity of 50m/s can enter a wall upto a depth of 10cm ,how much will be the average resistance offered by the wall?
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