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Find the altitude of an equilateral triangle, when
each of its side is 'a' cm?
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Find the altitude of an equilateral triangle, wheneach of its side is ...
To find the altitude of an equilateral triangle with each side measuring 'a' cm, we can use geometric relations.

Understanding the Equilateral Triangle
- An equilateral triangle has all three sides of equal length: \( a \).
- All internal angles are \( 60^\circ \).

Visualizing the Altitude
- The altitude (height) of an equilateral triangle can be drawn from one vertex to the midpoint of the opposite side.
- This altitude divides the triangle into two 30-60-90 right triangles.

Using the Pythagorean Theorem
- In a 30-60-90 triangle, the sides are in the ratio \( 1 : \sqrt{3} : 2 \).
- The side opposite the \( 30^\circ \) angle is \( \frac{a}{2} \) (half of the base).
- The side opposite the \( 60^\circ \) angle is the altitude (h).

Calculating the Altitude
1. **Identify the sides**:
- Base = \( \frac{a}{2} \)
- Hypotenuse = \( a \)
- Altitude = \( h \)
2. **Apply the Pythagorean theorem**:
- \( a^2 = h^2 + \left(\frac{a}{2}\right)^2 \)
3. **Simplifying**:
- \( a^2 = h^2 + \frac{a^2}{4} \)
- Rearranging gives \( h^2 = a^2 - \frac{a^2}{4} = \frac{3a^2}{4} \)
4. **Finding h**:
- \( h = \sqrt{\frac{3a^2}{4}} = \frac{a\sqrt{3}}{2} \)

Final Result
- The altitude \( h \) of an equilateral triangle with side \( a \) is given by:
**\[ h = \frac{a\sqrt{3}}{2} \]**
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