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The probability of throwing more than 4 in a single throw from an ordinary die?
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The probability of throwing more than 4 in a single throw from an ordi...
Understanding the Probability of Throwing More than 4 on a Die
When rolling a standard six-sided die, the outcomes are the numbers 1, 2, 3, 4, 5, and 6. To find the probability of rolling a number greater than 4, we need to follow these steps:

Identifying Favorable Outcomes
- The favorable outcomes for this scenario are:
- 5
- 6
Thus, there are 2 outcomes that are greater than 4.

Total Possible Outcomes
- A standard die has a total of 6 possible outcomes:
- 1
- 2
- 3
- 4
- 5
- 6
This means that the total number of possible outcomes when rolling the die is 6.

Calculating the Probability
- The probability (P) of an event is calculated using the formula:
\[
P(\text{Event}) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Possible Outcomes}}
\]
- For our scenario, the calculation becomes:
\[
P(\text{Rolling more than 4}) = \frac{2}{6} = \frac{1}{3}
\]

Conclusion
The probability of rolling a number greater than 4 on a single throw of an ordinary die is:
- \(\frac{1}{3}\) or approximately 0.3333 (33.33%).
Understanding these concepts helps in grasping the fundamentals of probability in various scenarios, making it essential for CA Foundation studies.
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The probability of throwing more than 4 in a single throw from an ordinary die?
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The probability of throwing more than 4 in a single throw from an ordinary die? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The probability of throwing more than 4 in a single throw from an ordinary die? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability of throwing more than 4 in a single throw from an ordinary die?.
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