The probability of throwing more than 4 in a single throw from an ordi...
Probability of throwing more than 4 in a single throw from an ordinary die:
To calculate the probability of throwing more than 4 in a single throw from an ordinary die, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Favorable outcomes:
In a single throw from an ordinary die, the favorable outcomes are the numbers 5 and 6. So, there are 2 favorable outcomes.
Total possible outcomes:
In a single throw from an ordinary die, there are 6 possible outcomes, which are the numbers 1, 2, 3, 4, 5, and 6.
Probability:
The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.
Probability = Number of favorable outcomes / Total number of possible outcomes
In this case, the probability of throwing more than 4 in a single throw from an ordinary die is:
Probability = 2 / 6
Simplifying the above fraction, we get:
Probability = 1 / 3
Therefore, the correct answer is option 'B' - 1/3.