An electric motor winds 200 turns of a thin coper wire on a uniform ro...
Problem Explanation:
An electric motor winds 200 turns of a thin copper wire on a uniform rod of diameter 10 cm in 2 seconds. We need to find the length of the wire that is wound over the rod in one second.
Solution:
Step 1: Find the circumference of the rod:
The diameter of the rod is given as 10 cm. To find the circumference of the rod, we can use the formula:
Circumference = π * Diameter
Plugging in the values, we get:
Circumference = π * 10 cm
Circumference = 31.4 cm (approximately)
Step 2: Find the length of wire wound in 2 seconds:
The problem states that 200 turns of wire are wound on the rod in 2 seconds. Since each turn covers the circumference of the rod, the length of wire wound in 2 seconds is:
Length of wire in 2 seconds = 200 * Circumference
Length of wire in 2 seconds = 200 * 31.4 cm
Step 3: Find the length of wire wound in 1 second:
To find the length of wire wound in 1 second, we can divide the length of wire wound in 2 seconds by 2:
Length of wire in 1 second = Length of wire in 2 seconds / 2
Length of wire in 1 second = (200 * 31.4 cm) / 2
Length of wire in 1 second = 3140 cm / 2
Length of wire in 1 second = 1570 cm
Step 4: Conversion to meters:
The length of wire wound in 1 second is given in centimeters. To convert it to meters, we need to divide it by 100:
Length of wire in 1 second = 1570 cm / 100
Length of wire in 1 second = 15.7 m
Therefore, the length of the wire that is wound over the rod in one second is 15.7 meters.
An electric motor winds 200 turns of a thin coper wire on a uniform ro...
An electric motor winds 200 turns of a thin copper wire on a uniform rod of diameter 10 cm , in 2 seconds . Then the length of the wire that is wound over the rod is one second is _m. anshu346h is waiting for your help.
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