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The equation of current in a purely inductive
circuit is 5sin(49 it- 30°). If the inductance is
30 mH then the equation for the voltage across
the inductor, will be?
Most Upvoted Answer
The equation of current in a purely inductivecircuit is 5sin(49 it- 30...
To derive the voltage across an inductor in a purely inductive circuit, we can use the relationship between current and voltage in inductors.
Understanding the Current Equation
The given current equation is:
5sin(49 it - 30°)
- Amplitude of current (I) = 5 A
- Angular frequency (ω) = 49 rad/s
- Phase angle (φ) = -30°
Inductor Voltage Relationship
The voltage (V) across an inductor can be calculated using the formula:
V(t) = L * (di/dt)
Where:
- L = inductance (in henries)
- di/dt = derivative of current with respect to time
Calculating di/dt
1. Differentiating the current equation:
- I(t) = 5sin(49t - 30°)
- di/dt = 5 * 49 * cos(49t - 30°)
2. This simplifies to:
- di/dt = 245cos(49t - 30°)
Inductance Value
Given:
- L = 30 mH = 0.03 H
Calculating Voltage
Now substituting values into the voltage formula:
V(t) = L * (di/dt)
- V(t) = 0.03 * 245cos(49t - 30°)
- V(t) = 7.35cos(49t - 30°)
Final Voltage Equation
Therefore, the equation for the voltage across the inductor is:
V(t) = 7.35cos(49t - 30°)
This voltage leads the current by 90°, consistent with the phase relationship in purely inductive circuits.
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The equation of current in a purely inductivecircuit is 5sin(49 it- 30°). If the inductance is30 mH then the equation for the voltage acrossthe inductor, will be?
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