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A 2300 V three phase star connected synchronous motor has armature
resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph.
The motor is operated at 0.5 leading power factor and takes a current
of 200 A from supply. Calculate back EMF generated in the motor &
load angle.?
resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph.
The motor is operated at 0.5 leading power factor and takes a current
of 200 A from supply. Calculate back EMF generated in the motor &
load angle.?
Most Upvoted Answer
A 2300 V three phase star connected synchronous motor has armature res...
Given Data
- Line Voltage (V) = 2300 V
- Armature Resistance (Ra) = 0.2 ohm/ph
- Synchronous Reactance (Xs) = 2.2 ohm/ph
- Current (I) = 200 A
- Power Factor = 0.5 (Leading)
Calculating Phase Voltage
- Phase Voltage (Vph) = V / √3 = 2300 / √3 ≈ 1325.9 V
Calculating Armature Current in Each Phase
- Iph = I = 200 A (since it is star-connected)
Calculating Voltage Drop Across Armature Resistance
- Voltage Drop (V_Ra) = Iph * Ra = 200 * 0.2 = 40 V
Calculating Voltage Drop Across Synchronous Reactance
- Voltage Drop (V_Xs) = Iph * Xs = 200 * 2.2 = 440 V
Calculating Back EMF (E)
- Using the formula: E = Vph + V_Ra + V_Xs
- E = 1325.9 + 40 + 440 = 1805.9 V
Calculating Load Angle (δ)
- Power Factor Angle (φ) = cos⁻¹(0.5) = 60 degrees
- Load Angle (δ) = φ = 60 degrees
Results
- Back EMF (E): Approximately 1805.9 V
- Load Angle (δ): 60 degrees
This analysis provides insights into the synchronous motor's performance, indicating a significant back EMF with a leading power factor.
- Line Voltage (V) = 2300 V
- Armature Resistance (Ra) = 0.2 ohm/ph
- Synchronous Reactance (Xs) = 2.2 ohm/ph
- Current (I) = 200 A
- Power Factor = 0.5 (Leading)
Calculating Phase Voltage
- Phase Voltage (Vph) = V / √3 = 2300 / √3 ≈ 1325.9 V
Calculating Armature Current in Each Phase
- Iph = I = 200 A (since it is star-connected)
Calculating Voltage Drop Across Armature Resistance
- Voltage Drop (V_Ra) = Iph * Ra = 200 * 0.2 = 40 V
Calculating Voltage Drop Across Synchronous Reactance
- Voltage Drop (V_Xs) = Iph * Xs = 200 * 2.2 = 440 V
Calculating Back EMF (E)
- Using the formula: E = Vph + V_Ra + V_Xs
- E = 1325.9 + 40 + 440 = 1805.9 V
Calculating Load Angle (δ)
- Power Factor Angle (φ) = cos⁻¹(0.5) = 60 degrees
- Load Angle (δ) = φ = 60 degrees
Results
- Back EMF (E): Approximately 1805.9 V
- Load Angle (δ): 60 degrees
This analysis provides insights into the synchronous motor's performance, indicating a significant back EMF with a leading power factor.
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A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.?
Question Description
A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.?.
A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.?.
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A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.?, a detailed solution for A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.? has been provided alongside types of A 2300 V three phase star connected synchronous motor has armature resistance of 0.2 ohm/ph. and synchronous reactance of 2.2 ohm/ph. The motor is operated at 0.5 leading power factor and takes a current of 200 A from supply. Calculate back EMF generated in the motor & load angle.? theory, EduRev gives you an
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