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A body starts from rest and travels with an acceleration of 2 m/s². After t
seconds its velocity is 10 m/s. Then t is?
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A body starts from rest and travels with an acceleration of 2 m/s². Af...
Understanding Motion with Constant Acceleration
To find the time \( t \) when a body reaches a velocity of 10 m/s while starting from rest and accelerating at 2 m/s², we can use the basic equations of motion.
Given Data:
- Initial velocity (u) = 0 m/s (starts from rest)
- Acceleration (a) = 2 m/s²
- Final velocity (v) = 10 m/s
Using the Equation of Motion:
The equation to relate these variables is:
- v = u + at
Substituting the Values:
- 10 = 0 + (2 * t)
Solving for Time (t):
- Rearranging gives us:
- 10 = 2t
- Dividing both sides by 2:
- t = 10 / 2
- t = 5 seconds
Conclusion:
Thus, the time taken to reach a velocity of 10 m/s under constant acceleration of 2 m/s² is 5 seconds.
This straightforward calculation illustrates the relationship between acceleration, time, and velocity in linear motion. Understanding these concepts is crucial for solving problems in physics, particularly in competitive exams like UPSC.
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A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s. Then t is?
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