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A body starts from rest and travels with an acceleration of 2 m/s². After t
seconds its velocity is 10 m/s. Then t is?
seconds its velocity is 10 m/s. Then t is?
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A body starts from rest and travels with an acceleration of 2 m/s². Af...
Understanding Motion with Constant Acceleration
To find the time \( t \) when a body reaches a velocity of 10 m/s while starting from rest and accelerating at 2 m/s², we can use the basic equations of motion.
Given Data:
- Initial velocity (u) = 0 m/s (starts from rest)
- Acceleration (a) = 2 m/s²
- Final velocity (v) = 10 m/s
Using the Equation of Motion:
The equation to relate these variables is:
- v = u + at
Substituting the Values:
- 10 = 0 + (2 * t)
Solving for Time (t):
- Rearranging gives us:
- 10 = 2t
- Dividing both sides by 2:
- t = 10 / 2
- t = 5 seconds
Conclusion:
Thus, the time taken to reach a velocity of 10 m/s under constant acceleration of 2 m/s² is 5 seconds.
This straightforward calculation illustrates the relationship between acceleration, time, and velocity in linear motion. Understanding these concepts is crucial for solving problems in physics, particularly in competitive exams like UPSC.
To find the time \( t \) when a body reaches a velocity of 10 m/s while starting from rest and accelerating at 2 m/s², we can use the basic equations of motion.
Given Data:
- Initial velocity (u) = 0 m/s (starts from rest)
- Acceleration (a) = 2 m/s²
- Final velocity (v) = 10 m/s
Using the Equation of Motion:
The equation to relate these variables is:
- v = u + at
Substituting the Values:
- 10 = 0 + (2 * t)
Solving for Time (t):
- Rearranging gives us:
- 10 = 2t
- Dividing both sides by 2:
- t = 10 / 2
- t = 5 seconds
Conclusion:
Thus, the time taken to reach a velocity of 10 m/s under constant acceleration of 2 m/s² is 5 seconds.
This straightforward calculation illustrates the relationship between acceleration, time, and velocity in linear motion. Understanding these concepts is crucial for solving problems in physics, particularly in competitive exams like UPSC.
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A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s. Then t is?
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A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s. Then t is? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s. Then t is? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s. Then t is?.
A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s. Then t is? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s. Then t is? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body starts from rest and travels with an acceleration of 2 m/s². After t seconds its velocity is 10 m/s. Then t is?.
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