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 If the sum of n terms of an AP is 3n2+5n then which of its terms is 164?​
  • a)
    27th
  • b)
    29th
  • c)
    28th
  • d)
    26th
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If the sum of n terms of an AP is 3n2+5n then which of its terms is 16...
Sn=3n^2+5n

S1=a1=3(1)^2+5(1)=8

S2=3(2)^2+5(2)=22

S2=22=a1+a2

a2=22-8=14

d=a2-a1=14-8=6

n^th term value is 164,then what is n?

n^th term=a+(n-1)d

164=8+(n-1)6

164-8 / 6=n-1

156/6=n-1

26+1=n

n=27

So 27^th term is 164.
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Community Answer
If the sum of n terms of an AP is 3n2+5n then which of its terms is 16...
Given: Sum of n terms of an AP = 3n^2+5n

To find: Which term is 164?

Solution:
Let's assume that the first term of the AP is 'a' and the common difference is 'd'.

The sum of n terms of an AP can be expressed as:
S_n = n/2 [2a + (n-1)d]

We are given that S_n = 3n^2+5n
So, we can write:
3n^2+5n = n/2 [2a + (n-1)d]

Simplifying this equation, we get:
6n^2 + 10n = n(2a + (n-1)d)

Dividing both sides by n, we get:
2a + (n-1)d = 6n + 10

Now, we know that the nth term of an AP can be expressed as:
a_n = a + (n-1)d

We need to find the value of n for which a_n = 164.

Substituting a_n = 164 and simplifying, we get:
n^2 + 4n - 41 = 0

Solving this quadratic equation, we get:
n = 5 or n = -9

Since n has to be a positive integer, we can ignore n = -9.

Therefore, the required term is the 27th term (when n = 5).

Hence, the correct answer is option 'A'.
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