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Designate the following complexes X, Y and Z as inert or labile.
X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3-
X and Y are inert, Z is labile
X and Z are labile, Y is inert
X is inert, Y and Z are labile
X is labile, Y and Z are inert?
X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3-
X and Y are inert, Z is labile
X and Z are labile, Y is inert
X is inert, Y and Z are labile
X is labile, Y and Z are inert?
Most Upvoted Answer
Designate the following complexes X, Y and Z as inert or labile. X = [...
Complex X: [Al(C2O4)3]3-
- Nature: Inert
- Reason: Aluminum is a small, highly charged ion, leading to strong ligand field stabilization. The oxalate ligands are bidentate, forming stable chelate rings, making the complex resistant to substitution.
Complex Y: [V(H2O)6]2+
- Nature: Labile
- Reason: Vanadium in this oxidation state has a relatively high energy barrier for ligand substitution. The presence of water as a weak field ligand allows for easier exchange, resulting in a more labile complex.
Complex Z: [Cr(C2O4)3]3-
- Nature: Inert
- Reason: Chromium(III) complexes are generally inert due to the strong ligand field created by the bidentate oxalate ligands. The chelation effect further stabilizes the complex, making it less prone to substitution.
Conclusion:
- Final Designation: X and Z are inert, while Y is labile.
- Overall Assessment: The stability of these complexes is influenced by the metal's oxidation state, the nature of the ligands, and chelation effects. In this case, X and Z exhibit inert behavior due to strong ligand interactions, while Y shows labile behavior due to the nature of its coordinating ligands.
- Nature: Inert
- Reason: Aluminum is a small, highly charged ion, leading to strong ligand field stabilization. The oxalate ligands are bidentate, forming stable chelate rings, making the complex resistant to substitution.
Complex Y: [V(H2O)6]2+
- Nature: Labile
- Reason: Vanadium in this oxidation state has a relatively high energy barrier for ligand substitution. The presence of water as a weak field ligand allows for easier exchange, resulting in a more labile complex.
Complex Z: [Cr(C2O4)3]3-
- Nature: Inert
- Reason: Chromium(III) complexes are generally inert due to the strong ligand field created by the bidentate oxalate ligands. The chelation effect further stabilizes the complex, making it less prone to substitution.
Conclusion:
- Final Designation: X and Z are inert, while Y is labile.
- Overall Assessment: The stability of these complexes is influenced by the metal's oxidation state, the nature of the ligands, and chelation effects. In this case, X and Z exhibit inert behavior due to strong ligand interactions, while Y shows labile behavior due to the nature of its coordinating ligands.
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Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert?
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Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert?.
Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert?.
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Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert?, a detailed solution for Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert? has been provided alongside types of Designate the following complexes X, Y and Z as inert or labile. X = [Al(C2O4)3]3-, Y = [V(H2O)6]2+, Z = [Cr(C2O4)3]3- X and Y are inert, Z is labile X and Z are labile, Y is inert X is inert, Y and Z are labile X is labile, Y and Z are inert? theory, EduRev gives you an
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