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2 students stand 0.8 m apart during a drill session if the mass of the students are fortification 48 kg respectively then what will be gravitational Force exerted between the 2 students?
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2 students stand 0.8 m apart during a drill session if the mass of the...
Gravitational Force Calculation
To find the gravitational force between two students, we use Newton's law of universal gravitation, which states that every mass attracts every other mass with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
Formula for Gravitational Force
The formula for gravitational force (F) is given by:
F = G * (m1 * m2) / r²
Where:
- F = gravitational force
- G = gravitational constant (6.674 × 10^-11 N(m/kg)²)
- m1 and m2 = masses of the two students
- r = distance between the centers of the two masses
Given Values
- Mass of student 1 (m1) = 48 kg
- Mass of student 2 (m2) = 48 kg
- Distance (r) = 0.8 m
Calculating the Gravitational Force
1. Identify the Values:
- m1 = 48 kg
- m2 = 48 kg
- r = 0.8 m
- G = 6.674 × 10^-11 N(m/kg)²
2. Substituting the Values:
- F = (6.674 × 10^-11) * (48 * 48) / (0.8)²
3. Calculating the Values:
- First calculate (48 * 48) = 2304
- Then calculate (0.8)² = 0.64
- Substitute these values into the formula:
- F = (6.674 × 10^-11) * (2304 / 0.64)
4. Final Calculation:
- F ≈ 2.513 × 10^-7 N
Conclusion
The gravitational force exerted between the two students is approximately 2.513 × 10^-7 Newtons, which is an extremely small force, illustrating the weak nature of gravitational interactions at the human scale.
To find the gravitational force between two students, we use Newton's law of universal gravitation, which states that every mass attracts every other mass with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
Formula for Gravitational Force
The formula for gravitational force (F) is given by:
F = G * (m1 * m2) / r²
Where:
- F = gravitational force
- G = gravitational constant (6.674 × 10^-11 N(m/kg)²)
- m1 and m2 = masses of the two students
- r = distance between the centers of the two masses
Given Values
- Mass of student 1 (m1) = 48 kg
- Mass of student 2 (m2) = 48 kg
- Distance (r) = 0.8 m
Calculating the Gravitational Force
1. Identify the Values:
- m1 = 48 kg
- m2 = 48 kg
- r = 0.8 m
- G = 6.674 × 10^-11 N(m/kg)²
2. Substituting the Values:
- F = (6.674 × 10^-11) * (48 * 48) / (0.8)²
3. Calculating the Values:
- First calculate (48 * 48) = 2304
- Then calculate (0.8)² = 0.64
- Substitute these values into the formula:
- F = (6.674 × 10^-11) * (2304 / 0.64)
4. Final Calculation:
- F ≈ 2.513 × 10^-7 N
Conclusion
The gravitational force exerted between the two students is approximately 2.513 × 10^-7 Newtons, which is an extremely small force, illustrating the weak nature of gravitational interactions at the human scale.
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2 students stand 0.8 m apart during a drill session if the mass of the students are fortification 48 kg respectively then what will be gravitational Force exerted between the 2 students?
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2 students stand 0.8 m apart during a drill session if the mass of the students are fortification 48 kg respectively then what will be gravitational Force exerted between the 2 students? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 2 students stand 0.8 m apart during a drill session if the mass of the students are fortification 48 kg respectively then what will be gravitational Force exerted between the 2 students? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 students stand 0.8 m apart during a drill session if the mass of the students are fortification 48 kg respectively then what will be gravitational Force exerted between the 2 students?.
2 students stand 0.8 m apart during a drill session if the mass of the students are fortification 48 kg respectively then what will be gravitational Force exerted between the 2 students? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 2 students stand 0.8 m apart during a drill session if the mass of the students are fortification 48 kg respectively then what will be gravitational Force exerted between the 2 students? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 students stand 0.8 m apart during a drill session if the mass of the students are fortification 48 kg respectively then what will be gravitational Force exerted between the 2 students?.
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