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2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?
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2 students stand 0.8 m apart during adrises if the mass of the student...
Gravitational Force Calculation
The gravitational force between two masses can be calculated using Newton's law of universal gravitation. The formula is given by:
F = G * (m1 * m2) / r^2
Where:
- F = gravitational force
- G = universal gravitational constant (6.674 × 10^-11 N(m/kg)^2)
- m1 and m2 = masses of the two objects
- r = distance between the centers of the two masses
Given Data
- Mass of Student 1 (m1) = 45 kg
- Mass of Student 2 (m2) = 48 kg
- Distance (r) = 0.8 m
Step-by-Step Calculation
- Step 1: Identify constants and values
- G = 6.674 × 10^-11 N(m/kg)^2
- m1 = 45 kg
- m2 = 48 kg
- r = 0.8 m
- Step 2: Substitute the values into the formula
- F = (6.674 × 10^-11) * (45 * 48) / (0.8^2)
- Step 3: Perform the calculations
- Calculate the product of masses: 45 * 48 = 2160 kg^2
- Calculate the square of distance: 0.8^2 = 0.64 m^2
- Substitute back into the formula: F = (6.674 × 10^-11) * (2160) / (0.64)
- Step 4: Final Calculation
- F ≈ (6.674 × 10^-11) * (3375) ≈ 2.25 × 10^-7 N
Conclusion
The gravitational force exerted between the two students is approximately 2.25 × 10^-7 N. This minuscule force highlights the weak nature of gravitational attraction between small masses at relatively close distances.
The gravitational force between two masses can be calculated using Newton's law of universal gravitation. The formula is given by:
F = G * (m1 * m2) / r^2
Where:
- F = gravitational force
- G = universal gravitational constant (6.674 × 10^-11 N(m/kg)^2)
- m1 and m2 = masses of the two objects
- r = distance between the centers of the two masses
Given Data
- Mass of Student 1 (m1) = 45 kg
- Mass of Student 2 (m2) = 48 kg
- Distance (r) = 0.8 m
Step-by-Step Calculation
- Step 1: Identify constants and values
- G = 6.674 × 10^-11 N(m/kg)^2
- m1 = 45 kg
- m2 = 48 kg
- r = 0.8 m
- Step 2: Substitute the values into the formula
- F = (6.674 × 10^-11) * (45 * 48) / (0.8^2)
- Step 3: Perform the calculations
- Calculate the product of masses: 45 * 48 = 2160 kg^2
- Calculate the square of distance: 0.8^2 = 0.64 m^2
- Substitute back into the formula: F = (6.674 × 10^-11) * (2160) / (0.64)
- Step 4: Final Calculation
- F ≈ (6.674 × 10^-11) * (3375) ≈ 2.25 × 10^-7 N
Conclusion
The gravitational force exerted between the two students is approximately 2.25 × 10^-7 N. This minuscule force highlights the weak nature of gravitational attraction between small masses at relatively close distances.
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2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?
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2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?.
2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?.
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