UPSC Exam > UPSC Questions > 2 students stand 0.8 m apart during adrises i...
Start Learning for Free
2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?
Most Upvoted Answer
2 students stand 0.8 m apart during adrises if the mass of the student...
Gravitational Force Calculation
The gravitational force between two masses can be calculated using Newton's law of universal gravitation. The formula is given by:
F = G * (m1 * m2) / r^2
Where:
- F = gravitational force
- G = universal gravitational constant (6.674 × 10^-11 N(m/kg)^2)
- m1 and m2 = masses of the two objects
- r = distance between the centers of the two masses
Given Data
- Mass of Student 1 (m1) = 45 kg
- Mass of Student 2 (m2) = 48 kg
- Distance (r) = 0.8 m
Step-by-Step Calculation
- Step 1: Identify constants and values
- G = 6.674 × 10^-11 N(m/kg)^2
- m1 = 45 kg
- m2 = 48 kg
- r = 0.8 m
- Step 2: Substitute the values into the formula
- F = (6.674 × 10^-11) * (45 * 48) / (0.8^2)
- Step 3: Perform the calculations
- Calculate the product of masses: 45 * 48 = 2160 kg^2
- Calculate the square of distance: 0.8^2 = 0.64 m^2
- Substitute back into the formula: F = (6.674 × 10^-11) * (2160) / (0.64)
- Step 4: Final Calculation
- F ≈ (6.674 × 10^-11) * (3375) ≈ 2.25 × 10^-7 N
Conclusion
The gravitational force exerted between the two students is approximately 2.25 × 10^-7 N. This minuscule force highlights the weak nature of gravitational attraction between small masses at relatively close distances.
The gravitational force between two masses can be calculated using Newton's law of universal gravitation. The formula is given by:
F = G * (m1 * m2) / r^2
Where:
- F = gravitational force
- G = universal gravitational constant (6.674 × 10^-11 N(m/kg)^2)
- m1 and m2 = masses of the two objects
- r = distance between the centers of the two masses
Given Data
- Mass of Student 1 (m1) = 45 kg
- Mass of Student 2 (m2) = 48 kg
- Distance (r) = 0.8 m
Step-by-Step Calculation
- Step 1: Identify constants and values
- G = 6.674 × 10^-11 N(m/kg)^2
- m1 = 45 kg
- m2 = 48 kg
- r = 0.8 m
- Step 2: Substitute the values into the formula
- F = (6.674 × 10^-11) * (45 * 48) / (0.8^2)
- Step 3: Perform the calculations
- Calculate the product of masses: 45 * 48 = 2160 kg^2
- Calculate the square of distance: 0.8^2 = 0.64 m^2
- Substitute back into the formula: F = (6.674 × 10^-11) * (2160) / (0.64)
- Step 4: Final Calculation
- F ≈ (6.674 × 10^-11) * (3375) ≈ 2.25 × 10^-7 N
Conclusion
The gravitational force exerted between the two students is approximately 2.25 × 10^-7 N. This minuscule force highlights the weak nature of gravitational attraction between small masses at relatively close distances.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?
Question Description
2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?.
2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?.
Solutions for 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? defined & explained in the simplest way possible. Besides giving the explanation of
2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students?, a detailed solution for 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? has been provided alongside types of 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? theory, EduRev gives you an
ample number of questions to practice 2 students stand 0.8 m apart during adrises if the mass of the students are 45 kg and 48 kg respectively then what will be gravitational Force exerted between the students? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup