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Hey there edurev ai
I am meghana
I wanted to know what would be the situation if
the linear magnification reduced by a spherical mirror is -1 and rising this value state the type of mirror under position of the object with respect to the pole of the mirror draw ray diagram to justify your answer?
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Hey there edurev aiI am meghanaI wanted to know what would be the situ...
Understanding Linear Magnification in Spherical Mirrors
When the linear magnification (m) of a spherical mirror is -1, it indicates that the image formed is of the same size as the object but inverted.
Type of Mirror
- The mirror in this case is a concave mirror.
Position of the Object
- The object is positioned at the center of curvature (C) of the mirror.
Ray Diagram Explanation
To illustrate this, we can draw a ray diagram:
1. Incident Ray Parallel to Principal Axis: When a ray of light parallel to the principal axis strikes the mirror, it reflects through the focal point (F).
2. Incident Ray through the Center of Curvature: A ray that passes through the center of curvature reflects back along the same path.
3. Point of Intersection: The two reflected rays intersect at a point below the principal axis, forming an inverted image at the same distance from the mirror as the object.
Characteristics of the Image
- Inverted: The image is inverted (due to negative magnification).
- Same Size: The height of the image is equal to the height of the object.
- Real Image: The image is real as it can be projected on a screen.
Conclusion
In summary, when the linear magnification is -1, the object is located at the center of curvature of a concave mirror, leading to the formation of an inverted, real, and equal-sized image. This behavior is crucial in applications like reflectors and telescopes, where precise image formation is required.
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Hey there edurev aiI am meghanaI wanted to know what would be the situation ifthe linear magnification reduced by a spherical mirror is -1 and rising this value state the type of mirror under position of the object with respect to the pole of the mirror draw ray diagram to justify your answer?
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