UPSC Exam > UPSC Questions > An object is placed 36 cm in front of a diver...
Start Learning for Free
An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.?
Most Upvoted Answer
An object is placed 36 cm in front of a diverging lens of focal length...
Calculations:
- Given data:
- Object distance, u = -36 cm
- Focal length, f = -24 cm
- Using the lens formula:
- 1/f = 1/v - 1/u
- 1/v = 1/f + 1/u
- 1/v = 1/-24 + 1/-36
- 1/v = -5/72
- v = -72/5
- v = -14.4 cm
- The negative sign indicates that the image is formed on the same side as the object, which means it is a virtual image.
- Magnification:
- Magnification, M = -v/u
- M = -(-14.4)/-36
- M = 0.4
- The negative sign in magnification indicates that the image is erect.
Graphical Method:
- Draw the optical axis, diverging lens, and the object at a distance of 36 cm from the lens.
- Draw a ray parallel to the optical axis, which appears to come from the focal point on the incident side.
- Draw a ray passing through the optical center without deviation.
- Trace the extended rays to find the point where they meet, giving the location of the virtual image.
- Measure the magnification by comparing the size of the image with the object.
This method visually represents how the virtual image is formed by the diverging lens and allows for a better understanding of the image characteristics.
- Given data:
- Object distance, u = -36 cm
- Focal length, f = -24 cm
- Using the lens formula:
- 1/f = 1/v - 1/u
- 1/v = 1/f + 1/u
- 1/v = 1/-24 + 1/-36
- 1/v = -5/72
- v = -72/5
- v = -14.4 cm
- The negative sign indicates that the image is formed on the same side as the object, which means it is a virtual image.
- Magnification:
- Magnification, M = -v/u
- M = -(-14.4)/-36
- M = 0.4
- The negative sign in magnification indicates that the image is erect.
Graphical Method:
- Draw the optical axis, diverging lens, and the object at a distance of 36 cm from the lens.
- Draw a ray parallel to the optical axis, which appears to come from the focal point on the incident side.
- Draw a ray passing through the optical center without deviation.
- Trace the extended rays to find the point where they meet, giving the location of the virtual image.
- Measure the magnification by comparing the size of the image with the object.
This method visually represents how the virtual image is formed by the diverging lens and allows for a better understanding of the image characteristics.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.?
Question Description
An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.?.
An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.?.
Solutions for An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? defined & explained in the simplest way possible. Besides giving the explanation of
An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.?, a detailed solution for An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? has been provided alongside types of An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? theory, EduRev gives you an
ample number of questions to practice An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (a) calculation and (b) the graphical method.? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup