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An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (b) the graphical method ( photo)?
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An object is placed 36 cm in front of a diverging lens of focal length...
Graphical Method for Finding Image Location and Magnification
Given data:
- Object distance (u) = -36 cm (negative sign indicates object is on the left side of the lens)
- Focal length (f) = -24 cm (negative sign indicates diverging lens)
- Image distance (v) = ?
- Magnification (m) = ?
Step 1: Determine the position of the image using the graphical method
1. Draw a ray diagram with the diverging lens.
2. Start by drawing a ray parallel to the principal axis that will refract through the focal point on the opposite side of the lens.
3. Draw a second ray passing through the optical center of the lens.
4. Where the two rays intersect after refraction will give the position of the image.
Step 2: Calculate the image distance and magnification
- The lens formula is given by: 1/f = 1/v + 1/u
- Substitute the given values into the formula: 1/-24 = 1/v + 1/-36
- Solve for v: v = -72 cm
- Calculate magnification using the formula: m = -v/u = -(-72)/-36 = 2
- The negative sign indicates the image is virtual and erect.
Therefore, the image is formed at a distance of 72 cm on the left side of the lens and is magnified with a magnification of 2.
Given data:
- Object distance (u) = -36 cm (negative sign indicates object is on the left side of the lens)
- Focal length (f) = -24 cm (negative sign indicates diverging lens)
- Image distance (v) = ?
- Magnification (m) = ?
Step 1: Determine the position of the image using the graphical method
1. Draw a ray diagram with the diverging lens.
2. Start by drawing a ray parallel to the principal axis that will refract through the focal point on the opposite side of the lens.
3. Draw a second ray passing through the optical center of the lens.
4. Where the two rays intersect after refraction will give the position of the image.
Step 2: Calculate the image distance and magnification
- The lens formula is given by: 1/f = 1/v + 1/u
- Substitute the given values into the formula: 1/-24 = 1/v + 1/-36
- Solve for v: v = -72 cm
- Calculate magnification using the formula: m = -v/u = -(-72)/-36 = 2
- The negative sign indicates the image is virtual and erect.
Therefore, the image is formed at a distance of 72 cm on the left side of the lens and is magnified with a magnification of 2.
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An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (b) the graphical method ( photo)?
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An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (b) the graphical method ( photo)? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (b) the graphical method ( photo)? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (b) the graphical method ( photo)?.
An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (b) the graphical method ( photo)? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (b) the graphical method ( photo)? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is placed 36 cm in front of a diverging lens of focal length 24cm. Find the location and magnification of the image formed by (b) the graphical method ( photo)?.
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