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Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 400 metre per second what is the average force applied on the rocket?
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Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 4...
Understanding the Problem
To calculate the average force applied on the Diwali rocket, we can use the concept of momentum and the formula for force, which is the rate of change of momentum.
Given Data
- Mass of smoke exhausted per second (m): 0.05 kg/s
- Speed of exhaust (v): 400 m/s
Calculating Momentum Change
- The momentum (p) of the exhaust per second can be calculated as:
p = m * v
Here, the mass flow rate (0.05 kg/s) is multiplied by the velocity (400 m/s).
- Therefore,
p = 0.05 kg/s * 400 m/s = 20 kg*m/s
Force Calculation
- According to Newton’s second law, the force (F) is equal to the rate of change of momentum. Since the momentum change occurs every second, we can say:
F = Δp/Δt
- Since we are considering a time interval of 1 second, Δt = 1 s, thus:
F = 20 kg*m/s / 1 s = 20 N
Conclusion
- The average force applied on the Diwali rocket is 20 Newtons.
This calculation illustrates how the rate of exhaust and the speed contribute directly to the thrust generated by the rocket, allowing it to ascend effectively during Diwali celebrations.
To calculate the average force applied on the Diwali rocket, we can use the concept of momentum and the formula for force, which is the rate of change of momentum.
Given Data
- Mass of smoke exhausted per second (m): 0.05 kg/s
- Speed of exhaust (v): 400 m/s
Calculating Momentum Change
- The momentum (p) of the exhaust per second can be calculated as:
p = m * v
Here, the mass flow rate (0.05 kg/s) is multiplied by the velocity (400 m/s).
- Therefore,
p = 0.05 kg/s * 400 m/s = 20 kg*m/s
Force Calculation
- According to Newton’s second law, the force (F) is equal to the rate of change of momentum. Since the momentum change occurs every second, we can say:
F = Δp/Δt
- Since we are considering a time interval of 1 second, Δt = 1 s, thus:
F = 20 kg*m/s / 1 s = 20 N
Conclusion
- The average force applied on the Diwali rocket is 20 Newtons.
This calculation illustrates how the rate of exhaust and the speed contribute directly to the thrust generated by the rocket, allowing it to ascend effectively during Diwali celebrations.
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Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 400 metre per second what is the average force applied on the rocket?
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Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 400 metre per second what is the average force applied on the rocket? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 400 metre per second what is the average force applied on the rocket? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 400 metre per second what is the average force applied on the rocket?.
Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 400 metre per second what is the average force applied on the rocket? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 400 metre per second what is the average force applied on the rocket? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Diwali rocket is exhausted 0.05 kg of smoke per second at a speed of 400 metre per second what is the average force applied on the rocket?.
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