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Heat of soln of CuSO4(s) and CuSO4.5H2O is 15.9 and 19.3 kJ/mol respectively. Find the heat of hydration of CuSO4(s)?
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Heat of soln of CuSO4(s) and CuSO4.5H2O is 15.9 and 19.3 kJ/mol respec...
Understanding the Problem
To find the heat of hydration of CuSO4(s), we can use the provided heat of solution values for both CuSO4(s) and CuSO4.5H2O. The heat of hydration is essentially the energy change associated with the dissolution of the anhydrous salt (CuSO4) when it forms the hydrated form (CuSO4.5H2O).
Heat of Solution Values
- Heat of solution of CuSO4(s): 15.9 kJ/mol
- Heat of solution of CuSO4.5H2O: 19.3 kJ/mol
Conceptual Approach
1. Dissolution Reaction:
- The dissolution of CuSO4(s) can be represented as:
CuSO4(s) → Cu^2+(aq) + SO4^2-(aq)
- The dissolution of CuSO4.5H2O can be represented as:
CuSO4.5H2O(s) → Cu^2+(aq) + SO4^2-(aq) + 5H2O(l)
2. Applying Hess's Law:
- The heat of hydration (ΔH_hyd) can be derived from the heat of solution:
ΔH_hyd = ΔH_solution (CuSO4.5H2O) - ΔH_solution (CuSO4)
Calculating Heat of Hydration
- Using the values:
ΔH_hyd = 19.3 kJ/mol - 15.9 kJ/mol
Final Calculation
- ΔH_hyd = 3.4 kJ/mol
Conclusion
The heat of hydration of CuSO4(s) is 3.4 kJ/mol, indicating that the process of hydration releases energy, making it exothermic. This value reflects the energy released when water molecules surround and stabilize the Cu^2+ and SO4^2- ions formed from the dissolution of anhydrous copper sulfate.
To find the heat of hydration of CuSO4(s), we can use the provided heat of solution values for both CuSO4(s) and CuSO4.5H2O. The heat of hydration is essentially the energy change associated with the dissolution of the anhydrous salt (CuSO4) when it forms the hydrated form (CuSO4.5H2O).
Heat of Solution Values
- Heat of solution of CuSO4(s): 15.9 kJ/mol
- Heat of solution of CuSO4.5H2O: 19.3 kJ/mol
Conceptual Approach
1. Dissolution Reaction:
- The dissolution of CuSO4(s) can be represented as:
CuSO4(s) → Cu^2+(aq) + SO4^2-(aq)
- The dissolution of CuSO4.5H2O can be represented as:
CuSO4.5H2O(s) → Cu^2+(aq) + SO4^2-(aq) + 5H2O(l)
2. Applying Hess's Law:
- The heat of hydration (ΔH_hyd) can be derived from the heat of solution:
ΔH_hyd = ΔH_solution (CuSO4.5H2O) - ΔH_solution (CuSO4)
Calculating Heat of Hydration
- Using the values:
ΔH_hyd = 19.3 kJ/mol - 15.9 kJ/mol
Final Calculation
- ΔH_hyd = 3.4 kJ/mol
Conclusion
The heat of hydration of CuSO4(s) is 3.4 kJ/mol, indicating that the process of hydration releases energy, making it exothermic. This value reflects the energy released when water molecules surround and stabilize the Cu^2+ and SO4^2- ions formed from the dissolution of anhydrous copper sulfate.
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Question Description
Heat of soln of CuSO4(s) and CuSO4.5H2O is 15.9 and 19.3 kJ/mol respectively. Find the heat of hydration of CuSO4(s)? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Heat of soln of CuSO4(s) and CuSO4.5H2O is 15.9 and 19.3 kJ/mol respectively. Find the heat of hydration of CuSO4(s)? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Heat of soln of CuSO4(s) and CuSO4.5H2O is 15.9 and 19.3 kJ/mol respectively. Find the heat of hydration of CuSO4(s)?.
Heat of soln of CuSO4(s) and CuSO4.5H2O is 15.9 and 19.3 kJ/mol respectively. Find the heat of hydration of CuSO4(s)? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Heat of soln of CuSO4(s) and CuSO4.5H2O is 15.9 and 19.3 kJ/mol respectively. Find the heat of hydration of CuSO4(s)? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Heat of soln of CuSO4(s) and CuSO4.5H2O is 15.9 and 19.3 kJ/mol respectively. Find the heat of hydration of CuSO4(s)?.
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