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A hockey Puck with a mass of 0.3 kg slides on the horizontal fictional light surface of two forces act on the park as shown in figure the force F1 has a magnitude of 5 N and F2 has magnitude of 8 N . determine the acceleration of the puck.?
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A hockey Puck with a mass of 0.3 kg slides on the horizontal fictional...
Understanding the Problem
To determine the acceleration of the hockey puck, we start with the given values:
- Mass of the puck (m): 0.3 kg
- Force F1: 5 N
- Force F2: 8 N
Since the forces are acting on a horizontal surface, we will analyze the net force acting on the puck.
Calculating the Net Force
- If both forces are acting in the same direction, the net force (F_net) can be calculated as:
- F_net = F1 + F2 = 5 N + 8 N = 13 N
- Conversely, if the forces are acting in opposite directions, the net force is:
- F_net = F2 - F1 = 8 N - 5 N = 3 N (assuming F2 is greater).
Applying Newton's Second Law
According to Newton's Second Law of Motion, the acceleration (a) can be calculated using the formula:
- a = F_net / m
Now, we can substitute the values of net force and mass into the equation.
Calculating the Acceleration
1. If F1 and F2 are in the same direction:
- a = 13 N / 0.3 kg = 43.33 m/s²
2. If F1 and F2 are in opposite directions:
- a = 3 N / 0.3 kg = 10 m/s²
Conclusion
The acceleration of the hockey puck depends on the direction of the forces applied. If they act in the same direction, the acceleration is approximately 43.33 m/s². If they act in opposite directions, the acceleration is approximately 10 m/s².
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A hockey Puck with a mass of 0.3 kg slides on the horizontal fictional light surface of two forces act on the park as shown in figure the force F1 has a magnitude of 5 N and F2 has magnitude of 8 N . determine the acceleration of the puck.?
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